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PHP: ctype_xdigit - Manual
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Last updated: Thu, 31 May 2007

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ctype_xdigit

(PHP 4 >= 4.0.4, PHP 5)

ctype_xdigit — 16 進数を表す文字かどうかを調べる

説明

bool ctype_xdigit ( string $text )

与えられた文字列 text のすべての文字が 16 進の '数字' であるかどうかを調べます。

パラメータ

text

調べる文字列。

返り値

text のすべての文字が 16 進の '数字' つまり 10 進の数字または [A-Fa-f] だった場合に TRUE 、そうでない場合に FALSE を返します。

例 417. ctype_xdigit() の例

<?php
$strings
= array('AB10BC99', 'AR1012', 'ab12bc99');
foreach (
$strings as $testcase) {
    if (
ctype_xdigit($testcase)) {
        echo
"The string $testcase consists of all hexadecimal digits.\n";
    } else {
        echo
"The string $testcase does not consist of all hexadecimal digits.\n";
    }
}
?>

上の例の出力は以下となります。


The string AB10BC99 consists of all hexadecimal digits.
The string AR1012 does not consist of all hexadecimal digits.
The string ab12bc99 consists of all hexadecimal digits.

    

参考

ctype_digit()



add a note add a note User Contributed Notes
ctype_xdigit
tom at hgmail dot com
15-Jan-2006 05:36
This function shows its usefulness on a web site where a user is asked to entered a hexidecimal color code for a color. To prevent breaking W3C standard and having them enter in "neon-green" or the wrong type of code like 355511235.

In conjunction with strlen()  you could create a function like this:

function check_valid_colorhex($colorCode) {
    // If user accidentally passed along the # sign, strip it off
    $colorCode = ltrim($colorCode, '#');

    if (
          ctype_xdigit($colorCode) &&
          (strlen($colorCode) == 6 || strlen($colorCode) == 3))
               return true;

    else return false;
}

 
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