Don't confuse next with continue!
If you're a Perl developer starting with PHP, you might try to use "next" inside a loop to skip to the next iteration...
i.e.,
foreach ($things as $thing) {
if (something I don't like about $thing) {
next;
}
blah....
}
The php compiler will take next... but it's not going to work.
Do this instead:
foreach ($things as $thing) {
if (something I don't like about $thing) {
continue;
}
blah....
}
next
(PHP 4, PHP 5, PECL xmlreader:1.0-1.0.1)
next — 内部配列ポインタを進める
説明
mixed next ( array &$array )内部配列ポインタが次の場所を指すようにし、(ポインタ移動後の) その配列値を返します。それ以上要素がない場合は FALSE を返します。
next() は、ひとつの違いを除いて current() と同じです。 next() は要素を返す前に内部配列ポインタをひとつ先に進めます。 つまり、次の配列要素を返すとともに内部配列ポインタをひとつ進めるということです。 もし内部配列ポインタをひとつ進めた結果、 要素リストの最後の先まで行ってしまった場合、 next()は FALSE を返します。
警告
この関数は論理値 FALSE を返す可能性がありますが、FALSE として評価される 0 や "" といった値を返す可能性もあります。 詳細については 論理値の セクションを参照してください。この関数の返り値を調べるには ===演算子 を 使用してください。
注意: 配列中に boolean FALSE の要素が含まれていると、 それを配列の終わりと区別することができません。FALSE 要素を含む配列を順に処理するには、each() 関数を参照ください。
例 313. next() および類似関数の使用例
<?php
$transport = array('foot', 'bike', 'car', 'plane');
$mode = current($transport); // $mode = 'foot';
$mode = next($transport); // $mode = 'bike';
$mode = next($transport); // $mode = 'car';
$mode = prev($transport); // $mode = 'bike';
$mode = end($transport); // $mode = 'plane';
?>
next
gg2005 at gmail dot com
07-Feb-2007 06:32
07-Feb-2007 06:32
GPatmore
13-Oct-2006 04:14
13-Oct-2006 04:14
If your using a foreach loop, unless you for a reference, PHP will make a copy of the array to use it the loop.
So, when I need to take a different action for the last element in the array I use the following:
<?php
$ary = explode(',','a,b,c,d,e,f,g');
foreach($ary as $a){
print 'letter ' . $a;
if(next($ary)){
print '<br>';
}else{
print '<br>dun!';
}
}
?>
Output:
letter a
letter b
letter c
letter d
letter e
letter f
letter g
dun!
NOTE::
PHP5 has added an ability to reference the variable in a foreach like:
<?php
foreach($ary as &$a){}
?>
this will probably cause undesired results when using the method above.
also if the array is changed in any way as to cause the length of the original array to become different then the copy, it will not work.
Consider the following example:
<?php
$ary = explode(',','a,b,c,d,e,f,g');
foreach($ary as $a){
print 'letter ' . $a;
if(next($ary)){
unset($ary[count($ary) - 1]);
print '<br>';
}else{
print '<br>dun!';
}
}
?>
output:
letter a
letter b
letter c
letter d
dun!letter e
dun!letter f
dun!letter g
dun!
tom at nono dot be
27-Jul-2006 08:19
27-Jul-2006 08:19
I see some questions like "how can I know if an array has a next value without changing its internal pointer" and some pretty complicated responses that DO work mind you and in some cases you'll need them...
But suppose you just need a different action within a foreach loop when reaching the final item:
(it won't be usefull in every situation, but in most it will)
$numOfItems = count($someArray);
$counter = 0;
foreach ($someArray as $key => value){
$counter += 1;
if ($counter <> $numOfItems){
//here all next items exist
} else {
//final item
}
}
Sigmar
31-May-2006 07:02
31-May-2006 07:02
And if you want to know if there are any array elements in array before given key, you can use this function:
function any_array_keys_before($keyname, &$array) {
if (!is_array($array)) {
return false;
}
if (empty($keyname)) {
return false;
}
$set = false;
$count = 0;
foreach ($array as $key => $value) {
if ($set === false && $key != $keyname) {
$count ++;
} else if ($key == $keyname) {
$set = true;
}
}
return $count > 0 ? true : false;
}
Sigmar
31-May-2006 06:52
31-May-2006 06:52
If you want to check, if there are some more elements in array after given key, you can use the following function:
function more_array_keys($keyname, &$array) {
if (!is_array($array)) {
return false;
}
if (empty($keyname)) {
return false;
}
$set = false;
$count = 0;
foreach ($array as $key => $value) {
if ($set === true) {
$count++;
}
if ($key == $keyname) {
$set = true;
}
}
return $count > 0 ? true : false;
}
tino at infeon dot com
14-May-2006 12:48
14-May-2006 12:48
this may be handy and i didnt know where else to post it.. i need a simple function to cycle through an array i eventually made it into a class so i could have multiple cycles.. if you like it or find it usefull please email me and let me know
class Cycle
{
var $position;
var $dataArray;
var $dataArrayCount;
function Cycle()
{
$this->dataArray = func_get_args();
$this->dataArrayCount = count($this->dataArray);
}
function Display()
{
$this->position = (!isset($this->position) || $this->position >= ($this->dataArrayCount - 1)) ? 0 : $this->position += 1;
return $this->dataArray[$this->position];
}
}
$bgColor = new Cycle('#000000', '#FFFFFF', '#FF0000');
echo $bgcolor->Display();
//returns #000000
echo $bgcolor->Display();
//returns #FFFFFF
echo $bgcolor->Display();
//returns #FF0000
echo $bgcolor->Display();
//returns #000000
brentimus
29-Apr-2005 02:10
29-Apr-2005 02:10
Papipo's function below is usefull in concept but does not work.
"Since you do not pass the array by reference, its pointer is only moved inside the function."
This is true, but the array you are manipulating in your has_next() function will have it's pointer set to the first element, not the same position as the original array. What you want to do is pass the array to the has_next() function via reference. While in the has_next() function, make a copy of the array to work on. Find out the current pointer position of the original array and set the pointer on the working copy of the array to the same element. Then you may test to see if the array has a "next" element.
Try the followig insetad:
<?php
function has_next(&$array)
{
$A_work=$array; //$A_work is a copy of $array but with its internal pointer set to the first element.
$PTR=current($array);
array_set_pointer($A_work, $PTR);
if(is_array($A_work))
{
if(next($A_work)===false)
return false;
else
return true;
}
else
return false;
}
function array_set_pointer(&$array, $value)
{
reset($array);
while($val=current($array))
{
if($val==$value)
break;
next($array);
}
}
?>
papipo's gmail account
13-Oct-2004 05:47
13-Oct-2004 05:47
I need to know if an array has more items, but without moving array's internail pointer. Thats is, a has_next() function:
<?php
function has_next($array) {
if (is_array($array)) {
if (next($array) === false) {
return false;
} else {
return true;
}
} else {
return false;
}
}
$array = array('fruit', 'melon');
if (has_next($array)) {
echo next($array);
}
// prints 'melon'
?>
Since you do not pass the array by reference, its pointer is only moved inside the function.
Hope that helps.
lukasz at karapuda dot com
19-Aug-2004 02:06
19-Aug-2004 02:06
This function will return the previous,next neighbors of an array entry within an associative array. If the specified $key points to the last or first element of the array, the first or last keys of the array will be returned consecutively. This is an improved version of the same function posted earlier.
<?php
function array_neighbor($arr, $key)
{
$keys = array_keys($arr);
$keyIndexes = array_flip($keys);
$return = array();
if (isset($keys[$keyIndexes[$key]-1])) {
$return[] = $keys[$keyIndexes[$key]-1];
}
else {
$return[] = $keys[sizeof($keys)-1];
}
if (isset($keys[$keyIndexes[$key]+1])) {
$return[] = $keys[$keyIndexes[$key]+1];
}
else {
$return[] = $keys[0];
}
return $return;
}
?>
court shrock
21-May-2004 08:36
21-May-2004 08:36
This code returns neighbors of the specified key. The result will be empty if it doesn't have any neighbors. My approach was to use the order of keys to determine neighbors, which is differnet from just getting the next/previous element in an array. Feel free to point out stupidities :)
<?php
function array_neighbor($arr, $key)
{
krsort($arr);
$keys = array_keys($arr);
$keyIndexes = array_flip($keys);
$return = array();
if (isset($keys[$keyIndexes[$key]-1]))
$return[] = $keys[$keyIndexes[$key]-1];
if (isset($keys[$keyIndexes[$key]+1]))
$return[] = $keys[$keyIndexes[$key]+1];
return $return;
}
?>
bm at ANTISPAM dot solidwave dot com
17-Apr-2004 01:49
17-Apr-2004 01:49
Take care when replacing code using reset()/next() with code using foreach as foreach does not update the array's internal pointer. This means you cannot, say, use next() to skip an element in foreach loop, or use current() within a function to get a reference to the current element. You probably have code depending on this internal pointer and replacing it will be more work than you anticipated.
See http://www.php.net/foreach