To toolofthesystem at gmail dot com:
You don't need to use output buffering with vprintf() because you can use vsprintf(), which has the same functionality as vprintf(), except that it returns the resulting string instead of outputting it.
vprintf
(PHP 4 >= 4.0.7, PHP 5)
vprintf — フォーマットされた文字列を出力する
説明
int vprintf ( string $format, array $args )formatに基づき文字列フォーマットされた文字 列を出力します。(フォーマットはsprintf()のドキュ メントに既述されています。)
printf()と動作は同じですが、可変長の引数ではな く、配列を引数として受け取ります。
出力された文字列の長さを返します。
printf(), sprintf(), vsprintf() も参照ください。
vprintf
tehjosh at gamingg dot net
30-Jul-2007 11:19
30-Jul-2007 11:19
toolofthesystem at gmail dot com
28-Mar-2007 01:42
28-Mar-2007 01:42
This function comes useful sometimes when trying to list information returned from MySQL:
function print_sql($query,$printf){
$sql_sql = mysql_query($query);
while($sql = mysql_fetch_row($sql_sql)){
vprintf($printf,$sql);
}
}
Unfortunately, this seems to sneak its way past output buffering when I tried creating an argument to allow it to be contained in a returned string... either that or I didn't do it right.
soylent at soylentgreens dot com
10-Dec-2006 06:49
10-Dec-2006 06:49
I wanted to achieve (something like) this:
<?
$format = "A %s %s %s.\n";
$array1 = Array("monkey", "cow", "rooster");
$array2 = Array("eats", "goes", "crows");
$array3 = Array("bananas", "moo", "in the morning");
printf($format, $array1, $array2, $array3);
?>
Output:
A monkey eats bananas.
A cow goes moo.
A rooster crows in the morning.
but I couldn't find any php function to put in for printf that would work (vprintf comes close). So I created this little function (and used it to create a select box):
<?
/*
printf_arrays( string format, [array args[, array ...]] )
*/
function printf_arrays($format) {
$args = func_get_args();
array_shift($args); // get rid of format
for($i=0; $i<count($args[0]); $i++) {
$pfargs = Array();
foreach($args as $arr) $pfargs[] = (is_array($arr) && $arr[$i]) ? $arr[$i] : '';
vprintf($format, $pfargs);
}
}
$months = Array(
'01'=>'Jan',
'02'=>'Feb',
/* etc. */
);
?>
<select name="month">
<? printf_arrays('<option value="%s">%s</option>', array_keys($months), array_values($months)) ?>
</select>
Anyone else have any better ideas? Is there a built-in php function I missed that does this already?
caleb at tekhawk dot com
30-Nov-2006 07:19
30-Nov-2006 07:19
i know that you can use %1$s or %3$s to select the first or third string but how can you or can you use array names to select it
something like %'user'$s $'email'$s
i tend to add things to my databases over time and this could save loads of recoding
WebMaestro (asiby at hotmail dot com)
13-Mar-2005 05:40
13-Mar-2005 05:40
<?php
$fruits = array(1, 'banana',1, 'apples', 3, 'oranges', 2, 'peaches');
vprintf("I have %d %s, %d %s, %d %s and %d %s.", $fruits);
?>
Output:
I have 1 banana, 1 apples, 3 oranges and 2 peaches.