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PHP: pg_fetch_row - Manual
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Last updated: Thu, 31 May 2007

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pg_fetch_row

(PHP 4, PHP 5)

pg_fetch_row — 数値添字の配列として行を得る

説明

array pg_fetch_row ( resource $result [, int $row] )

pg_fetch_row() は、指定した result リソースが指す結果から 1 行分のデータを取得します。

注意: この関数は、 NULL フィールドに PHPの NULL 値を設定します。

注意: PHP 4.1.0 以降、row はオプションとなりました。

パラメータ

result

pg_query(), pg_query_params() あるいは pg_execute() から返される PostgreSQL の クエリ結果リソース。

row

結果から取得する行の番号。行番号は 0 から始まります。指定しなかった 場合は、次の行が読み込まれます。

返り値

個々の値を文字列として格納した配列を返します。配列の添字は 0 から 始まります。データベースの NULL 値は NULL として返します。

row が結果の行数より大きい場合・行が存在しない場合 、そしてそれ以外のエラーが発生した場合は FALSE を返します。

例 1876. pg_fetch_row() の例

<?php

$conn
= pg_pconnect("dbname=publisher");
if (!
$conn) {
  echo
"An error occured.\n";
  exit;
}

$result = pg_query($conn, "SELECT author, email FROM authors");
if (!
$result) {
  echo
"An error occured.\n";
  exit;
}

while (
$row = pg_fetch_row($result)) {
  echo
"Author: $row[0]  E-mail: $row[1]";
  echo
"<br />\n";
}
 
?>

参考

pg_query()
pg_fetch_array()
pg_fetch_object()
pg_fetch_result()



add a note add a note User Contributed Notes
pg_fetch_row
pletiplot at seznam dot cz
07-Jun-2006 07:18
Note, that when you retrieve some PG boolean value, you get 't' or 'f' characters which are not compatible with PHP bool.
post at zeller-johannes dot de
27-Apr-2005 06:51
I wondered whether array values of PostgreSQL are converted to PHP arrays by this functions. This is not the case, they are stored in the returned array as a string in the form "{value1 delimiter value2 delimiter value3}" (See http://www.postgresql.org/docs/8.0/interactive/arrays.html#AEN5389).
maxnamara at yahoo dot com
14-Oct-2004 04:03
Get downlines, put them into arrays.

function get_downlines($my_code){
    global $link;

    $sql = "select user_id, name from tb_user where parentcode = $my_code";
    $res = pg_query($link,$sql);
    if(!$res){
        echo "Error: ".$sql;exit();
    }
    $num_fields = pg_num_fields($res);
    $info_rows = 0;

    $num_rows = pg_num_rows($res);
    while($arr = pg_fetch_row($res)){

           $info_offset  = 1;
         $info_columns  = 0;

        while ($info_offset <= $num_fields) {
                 $info_elements[$info_rows][$info_columns] = $arr[$info_columns];
                 $info_offset++; $info_columns++;
        }
        $info_rows++;           
    }
return $info_elements;
}
Matthew Wheeler
23-May-2003 01:29
Note that the internal row counter is incremented BEFORE the row is retrieved. This causes an off by one error if you try to do:

pg_result_seek($resid,0);
pg_fetch_row($resid);

you will get back the SECOND result not the FIRST.
imantr at cbn dot net dot id
24-Jul-2002 12:38
I use the following code to assigning query result to an array.

while ($row = pg_fetch_row($result)) $newArray[] = $row[0];

print_r($newArray);
darw75 at swbell dot net
23-Aug-2001 09:39
a way to do this with 2 loops to insert data into a table...

$num = pg_numrows($result);
$col_num = pg_numfields($result);

for ($i=0; $i<$num; $i++) {
  $line  = pg_fetch_array($result, $i, PGSQL_ASSOC);
  print "\t<tr bgcolor=#dddddd>\n";
    for ($j=0; $j<$col_num; $j++){
    list($col_name, $col_value) =each($line);
    print "\t\t<TD ALIGN=RIGHT><FONT SIZE=1 FACE='Geneva'>$col_value</FONT></TD>\n";
    }
  echo "<br>";
  }
rtreat2 at tampabay dot rr dot com
24-Oct-2000 09:41
the mysql way....

$rows = pg_numrows($result);
for ($i=0; $i < $rows; $i++){
    list($foo,$bar) = pg_fetch_row($result,$i);

    print ("$foo , $bar)\n");
}

 
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