<?
//this wil give you a nice view over your used classes.
//in my config-file i've loaded my classes
//this script gives you a class-diagram
//still need to something about the javascript feature...
//hope it helps you :)
include("config.php");
function drawClass($c){
if($c['beschrijving']){
echo "<table style=\"background-color: #FFFFCC; border: 1px solid black;\">".$c['beschrijving'];
}
foreach($c as $k=>$sub){
if($k!="beschrijving"){
echo "<tr><td>";
drawClass($c[$k],($i+1));
echo "</td></tr>";
}
}
if($c['beschrijving']){
echo "</table><br>";
}
}
?>
<html>
<head>
<style>
*{
font-family: Verdana;
font-size: 10pt;
}
</style>
<script>
var mem=new Array();
function up(id){
if(!mem[id]) mem[id]=true;
else mem[id]=false;
if(mem[id]) document.getElementById(id).style.visibility="hidden";
else document.getElementById(id).style.visibility="visible";
}
</script>
</head>
<body>
<?
$list=array();
$classes=get_declared_classes();
foreach($classes as $k=>$v){
$vars_p=array();
$meth_p=array();
$parent=array($v);
$parent_tmp=$v;
$target= &$list;
while($parent_tmp=get_parent_class($parent_tmp)){
array_push($parent,$parent_tmp);
$vars_p=array_merge($vars_p,get_class_vars($parent_tmp));
$meth_p=array_merge($meth_p,get_class_methods($parent_tmp));
}
for($i=count($parent)-1;$i>=0;$i--){
if(!is_array($target[$parent[$i]])){
$target[$parent[$i]]=array();
}
$target= &$target[$parent[$i]];
}
$str="<tr><td style=\"background-color: #FFCC66;\"><button onclick=\"up('$v');\">UP</button>";
foreach($parent as $itt=>$p) $str.=($itt>0?"::":"").$p;
$str.="</td></tr><tr><td>";
$str.="<table style=\"background-color: #FFFFCC; width: 300px;\" id=\"".$v."\">";
$vars=get_class_vars($v);
foreach($vars as $l=>$w){
if(!is_numeric(array_search($l,array_keys($vars_p)))){
$str.="<tr><td>var ".$l.($w?"=".$w:"").";</td></tr>";
}
}
$meth=get_class_methods($v);
foreach($meth as $l=>$w){
if(!is_numeric(array_search($w,$meth_p))){
$str.="<tr><td>function ".$w."(){}</td></tr>";
}
}
$str.="</table></td></tr>";
$target['beschrijving']=$str;
}
drawClass($list);
?>
</body>
</html>
XII. Class/Object Functions
Introduction
These functions allow you to obtain information about classes and instance objects. You can obtain the name of the class to which an object belongs, as well as its member properties and methods. Using these functions, you can find out not only the class membership of an object, but also its parentage (i.e. what class is the object class extending).
Requirements
No external libraries are needed to build this extension.
Installation
There is no installation needed to use these functions; they are part of the PHP core.
Runtime Configuration
This extension has no configuration directives defined in php.ini.
Resource Types
This extension has no resource types defined.
Predefined Constants
This extension has no constants defined.
Examples
In this example, we first define a base class and an extension of the class. The base class describes a general vegetable, whether it is edible or not and what is its color. The subclass Spinach adds a method to cook it and another to find out if it is cooked.
Example 352. classes.inc
<?php
// base class with member properties and methods
class Vegetable {
var $edible;
var $color;
function Vegetable($edible, $color="green")
{
$this->edible = $edible;
$this->color = $color;
}
function is_edible()
{
return $this->edible;
}
function what_color()
{
return $this->color;
}
} // end of class Vegetable
// extends the base class
class Spinach extends Vegetable {
var $cooked = false;
function Spinach()
{
$this->Vegetable(true, "green");
}
function cook_it()
{
$this->cooked = true;
}
function is_cooked()
{
return $this->cooked;
}
} // end of class Spinach
?>
We then instantiate 2 objects from these classes and print out information about them, including their class parentage. We also define some utility functions, mainly to have a nice printout of the variables.
Example 353. test_script.php
<pre>
<?php
include "classes.inc";
// utility functions
function print_vars($obj)
{
foreach (get_object_vars($obj) as $prop => $val) {
echo "\t$prop = $val\n";
}
}
function print_methods($obj)
{
$arr = get_class_methods(get_class($obj));
foreach ($arr as $method) {
echo "\tfunction $method()\n";
}
}
function class_parentage($obj, $class)
{
if (is_subclass_of($GLOBALS[$obj], $class)) {
echo "Object $obj belongs to class " . get_class($$obj);
echo " a subclass of $class\n";
} else {
echo "Object $obj does not belong to a subclass of $class\n";
}
}
// instantiate 2 objects
$veggie = new Vegetable(true, "blue");
$leafy = new Spinach();
// print out information about objects
echo "veggie: CLASS " . get_class($veggie) . "\n";
echo "leafy: CLASS " . get_class($leafy);
echo ", PARENT " . get_parent_class($leafy) . "\n";
// show veggie properties
echo "\nveggie: Properties\n";
print_vars($veggie);
// and leafy methods
echo "\nleafy: Methods\n";
print_methods($leafy);
echo "\nParentage:\n";
class_parentage("leafy", "Spinach");
class_parentage("leafy", "Vegetable");
?>
</pre>
One important thing to note in the example above is that
the object $leafy is an instance of the class
Spinach which is a subclass of
Vegetable,
therefore the last part of the script above will output:
[...]
Parentage:
Object leafy does not belong to a subclass of Spinach
Object leafy belongs to class spinach a subclass of Vegetable
Table of Contents
- call_user_method_array — Call a user method given with an array of parameters [deprecated]
- call_user_method — Call a user method on an specific object [deprecated]
- class_exists — Checks if the class has been defined
- get_class_methods — Gets the class methods' names
- get_class_vars — Get the default properties of the class
- get_class — Returns the name of the class of an object
- get_declared_classes — Returns an array with the name of the defined classes
- get_declared_interfaces — Returns an array of all declared interfaces
- get_object_vars — Gets the properties of the given object
- get_parent_class — Retrieves the parent class name for object or class
- interface_exists — Checks if the interface has been defined
- is_a — Checks if the object is of this class or has this class as one of its parents
- is_subclass_of — Checks if the object has this class as one of its parents
- method_exists — Checks if the class method exists
- property_exists — Checks if the object or class has a property
Class/Object Functions
19-Nov-2006 12:38
02-Sep-2006 12:40
Note to the solution by 'zabmilenko at hotmail dot com':
Good idea but encapsulation is a better technique which is also more portable and reliable.
You can pass an object which is based on an interface/superclass to the common DB interface.
For instance:
<?php
class DB_Common {
// data can be either an uri or array depending on how you construct it
// e.g. data = array('host' => 'x.x.x.x', 'port' => '65535', 'etc' => '...')
function connect($data) { die("must be overriden by subclass"); }
function disconnect() { die("..."); }
function query($query) { die("..."); }
}
class DB_MySQL extends DB_Common { /* override methods here */ }
class DB_PgSQL extends DB_Common { /* same here */
class DB_Frontend {
var $errmsg = array('DB_Common subclass-string or object required');
var $_db;
// PHP4/5 compat
function DB_Frontend($arg) { $this->__construct($arg); }
function __construct($arg) {
if( is_object($arg) && is_a($arg, 'DB_Common') )
$this->_db = $arg;
else
{
if( !is_string($arg) )
die($this->errmsg[0]);
$arg = "DB_$arg";
if( !class_exists($arg) )
die($this->errmsg[0]);
$this->_db = new $arg;
// use is_subclass_of(object, string) for compat with older versions
if( !is_subclass_of($arg, 'DB_Common') )
die($this->errmsg[0]);
}
}
// add connect, disconnect that simply calls $this->_db->method() instead
function getOne($quey) {
// preprocess query if needed
$result = $this->_db->query($query);
// process result if needed
return $result;
}
/* add more methods if needed */
}
// string parameter
$frontend = new DB_Frontend('MySQL');
// object parameter
$backend = new DB_MySQL();
$frontend = new DB_Frontend($backend);
?>
You can also use a static DB class. If you see PEAR::DB you will see how all this is quite equal to eachother. The main difference is the frontend class which should encapsulte the backend.
Suggestions and/or comments appreciated.
20-Jul-2006 10:18
function from Tobias K.....
stdClass Object to XML
xml:
[CODE]
"$xml<?xml version='1.0' standalone='yes'?>" .
"<movies>" .
"<movie eur=\"10.00\">" .
"<title>PHP: Behind the Parser</title>" .
"<characters>" .
"<character>" .
"<name>Ms. Coder</name>" .
"<actor>Onlivia Actora</actor>" .
"</character>" .
"<character>" .
"<name>Mr. Coder</name>" .
"<actor>El ActÓr</actor>" .
"</character>" .
"</characters>" .
"<plot>" .
"Text bla bla." .
"</plot>" .
"<rating ulf=\"integer\">7</rating>" .
"<rating type=\"stars\">5</rating>" .
"</movie>" .
"</movies>";
[/CODE]
stdObject:
[CODE]
stdClass Object
(
[movie] => stdClass Object
(
[title] => PHP: Behind the Parser
[characters] => stdClass Object
(
[character] => Array
(
[0] => stdClass Object
(
[name] => Ms. Coder
[actor] => Onlivia Actora
)
[1] => stdClass Object
(
[name] => Mr. Coder
[actor] => El ActÓr
)
)
)
[plot] => Text bla bla.
[rating] => Array
(
[0] => stdClass Object
(
[_] => 7
[ulf] => integer
)
[1] => stdClass Object
(
[_] => 5
[type] => stars
)
)
[eur] => 10
)
)
[/CODE]
Aufruf:
[PHP]
$s = htmlentities(asXML($r,"movies",array(
"movies/movie" => "eur",
"movies/movie/rating" => "ulf type"
)));
[/PHP]
Funktion:
[PHP]
function asXML($obj, $name, $attrNames=NULL, &$xml="", $path="", $depth=0) {
if (is_array($obj)) {
foreach ($obj as $v)
asXML($v,$name,$attrNames,$xml,$path,$depth);
} else {
if ($path) $xml .= "\n";
$path = $path ? "$path/$name" : $name;
$indent = str_repeat(" ",$depth*4);
$xml .= "$indent<$name";
$attr = $attrNames[$path];
if ($attr) {
if (!is_object($obj))
throw new Exception("asXML(): ".
"$path is no object, so it cannot hold attributes");
$attr = explode(" ",$attr);
foreach ($attr as $key)
if ($obj->$key) $xml .= " $key=\"{$obj->$key}\"";
}
$xml .= ">";
if (is_object($obj)) {
$xml .= $obj->_;
$len = strlen($xml);
foreach (get_object_vars($obj) as $key => $value)
if ($key!="_" && (!is_array($attr) || !in_array($key,$attr)))
asXML($value,$key,$attrNames,$xml,$path,$depth+1);
if ($len!=strlen($xml)) $xml .= "\n$indent";
} else {
$xml .= $obj;
}
$xml .= "</$name>";
}
return $xml;
}
[/PHP]
26-Oct-2005 07:06
You could reformat your query to use the 'as colname'
<? $db->query("select found_rows() as found_rows"); ?>
13-Oct-2005 11:21
Subject: using "sql_calc_found_rows" in a MySQL query while exploiting result in a PHP db class object.
Hello,
There is a nice function in MySQL that allows to know how many records would have been returned if no "where" clause were set : SQL_CALC_FOUND_ROWS.
If you have create a db object to collect the returned lines, you will be a little perplex when trying to call the result of this function.
Why ?
Simply because the returned field's name is "found_rows()" and obviously it's not possible to call something like :
<?php $result->found_rows() ?>
...as it will try to acces a method, not a property !
Then, the only way to get the right result seems to be the use of a class function, like :
<?php
$db->query("select found_rows()");
$count=current(get_object_vars(current($db->result)));
?>
Of course, if somebody found an other way to solve it, like a special syntax (see the one used with curled arrays in a string), I'm really open to discuss.
Good luck,
Pascal
03-Aug-2005 02:55
as for zabmilenko's solution:
wouldn't it be better to create it this way?
<?php
// The base class for all db classes
class DB {
protected $connectId;
}
// Class for MySQL, which extends base class
class MySQL extends DB {
function connect () {
$this->connectId = mysql_connect (...);
}
}
// Class for PostgreSQL, which extends base class
class pgSQL extends DB {
function connect () {
$this->connectId = pg_connect (...);
}
}
// and then call constructor like this:
$dbName = "MySQL";
$db = new $dbName ( ... );
// ... which creates an object of class MySQL
?>
27-Jun-2005 04:08
((PHP5))
I wanted to dynamically choose an extender for a class. This took awhile of playing with it but I came up with a solution. Note that I can't verify how safe it is, but it appears to work for me. Perhaps someone else can shed light on the details:
<?php
class A { var $value = "Class A\n"; }
class B { var $value = "Class B\n"; }
// Uncomment which extender you want. You can use variables as well.
// define('__EXTENDER__', 'A');
define('__EXTENDER__', 'B');
// Use eval to create a wrapper class.
eval('class EXTENDER extends '. __EXTENDER__ . ' { }');
class C extends EXTENDER
{
function __construct()
{
echo $this->value;
}
}
$t = new C;
?>
Outputs: Class B
Practical application: I have a database abstraction system that has individual classes for mysql, pgsql, et al. I want to be able to create a global db class that extends one of the individual db classes depending on the application configuration.
I know that there are probably much better ways of doing this but I haven't reached that level when it comes to classes.
04-Mar-2005 06:27
If anyone is interested in looking for a way to dynamically load existing objects into a class, here is what I found very useful.
//---------------------------------------------------------
// Dynamically load External Objects into a class
function objRef ( &$obj ) {
eval("\$this->obj_".get_class($obj)." = \$obj;");
}
//---------------------------------------------------------
// Reference by using: $this->obj_[object Name]->[var|f{}]
Example:
class date { function date ( ) { $this->date = "March 3rd"; } }
class time { function time ( ) { $this->time = "12:30pm"; } }
class show {
function objRef ( &$obj ){
eval("\$this->obj_".get_class($obj)." = \$obj;");
}
function test ( $var ){
echo "$var".$this->obj_date->date." @ ".$this->obj_time->time;
}
}
$date = new date;
$time = new time;
$show = new show;
$show->objRef($date);
$show->objRef($time);
$show->test("Time Now => ");
// Output: Time Now => March 3rd @ 12:30pm
I found the prefix 'obj_' before the class name useful because it helped me to automatically identify external object references when scanning through my scripts. You can omit this if you want. Hope this helps someone.
03-Mar-2005 03:25
to covertka at muohio dot edu and pillepop2003 at yahoo dot de:
There's a much easier solution to getting a class' name for working with a factory function. Let's assume you're doing something like this:
<?php
function FactoryFunction($whatever, $instancedata) {
switch ($whatever) {
case 'stuff' : return new Stuff($instancedata);
case 'otherstuff' : return new Otherstuff($instancedata);
}
}
?>
Now, consider the named parameter idiom and remember that PHP uses hashes for everything; as a result make the following changes:
<?php
function FactoryFunction($whatever, $instancedata) {
switch ($whatever) {
case 'stuff' : return array('typeis'=>'stuff', 'instance'=>new Stuff($instancedata));
case 'otherstuff' : return array('typeis'=>'otherstuff', 'instance'=>new Otherstuff($instancedata));
}
}
?>
Nice 'n simple. It seems that what the original poster wanted was something like C++ static data members; unfortunately as PHP4 has no static variables at all, there would need to be significant language change to support static-like behavior. If you move to PHP5, the static keyword solves your problem cleanly.
03-Jan-2005 10:27
To pillepop2003 at yahoo dot de:
I have the same issue. I have a base class that manages database tasks for a number of child classes. One of the functions in the base class is a find() method that returns instances of the child classes. Since find() is usually called as a static method, it needs to know the name of the child class. As you've found, this appears to be impossible to get in an easy fashion.
The only way I've found to get the child class name is to use the debug_traceback() function. This requires me to have a find() method in every child class, but it does work.
Here's an example:
<?php
require_once("Application.php");
class parentClass {
function find() {
$className = NULL;
foreach (debug_backtrace() as $bt) {
if ($bt['function'] == __FUNCTION__) {
$className = $bt['class'];
}
}
// here should be some code to find the proper id, let's assume it was id 1
$id = 1;
return new $className($id);
}
}
class foo extends parentClass {
function __construct($id) {
$this->id = id;
}
function find() {
return parent::find();
}
}
class bar extends parentClass {
function __construct($id) {
$this->id = id;
}
function find() {
return parent::find();
}
}
$a = foo::find();
printf("Type for \$a: %s<br/>\n", get_class($a));
$b = bar::find();
printf("Type for \$b: %s<br/>\n", get_class($b));
?>
05-Aug-2004 03:17
To pillepop2003 at yahoo dot de:
It seems to me if there really is no nice way to get the class name in an un-instanciated class, there is a workaround in PHP5 though using static/class variables.
Example:
<?php
class myFoo
{
static $__ClassName = __CLASS__;
static function getClassName()
{
return myFoo::$__ClassName;
}
};
class myFooExtended extends myFoo
{
function __construct()
{
myFooExtended::$__ClassName = __CLASS__;
};
};
?>
However, you'll need to have at least instanciated an object of the class myFooExtended before calling getClassName or introduce some other initialization (the class variable will need to be set at some point to __CLASS__ in the sub-class).
06-Jul-2004 11:58
As programmers, you're probably more organized than me, but, I do try and maintain some order in my classes and codes and separate them in "packages" as in java.
This helped me keep them organized but caused havok when trying to use them, so what I did was to create a class that handles the loading of classes (which I instanciate in all pages) along with my error handling class all bundled up. This way, I can load my classes with a command similar to
$baseClass->loadClass("package","className"[,"constructor"]);
the function responsible for this has some checking to see if they are loaded and stuff like that...
function loadClass($packageName,$className,$constructor=""){
// if you dont have a constructor declare any function inside
// the class
if ($constructor==""){
$constructor=$className;
}
if(!is_callable(array($className,$constructor))){
if (defined("CLASS_DIR")){
$pkg = CLASS_DIR.$packageName."/";
if (is_dir($pkg)){
// we have a directory with the package name
$cls = $pkg.$className.".class.php";
if(is_file($cls)){
// we have a file
include_once($cls);
}else{
die("Class <b>$className</b> could not be found in package <b>$packageName</b> , please check your instalation");
}
}else{
die("Package <b>$packageName</b> could not be found, please check your instalation");
}
}
}
}
Just remember to define CLASS_DIR as the physical path for the directories where you packages are...
Hope this comes in handy...
Here's an example of a diretory strucutre...
/var/www/classes/ <- this would be CLASS_DIR
in there I have:
package1/
name.class.php
name2.class.php
....
The loadClass would look like: loadClass("package1","name");
Cute and easy
19-Jun-2004 08:59
Re: Looking for an uninstantiated class
# Loads data from a table into a class object
class LFPDataFactory extends LFPObject {
var $object;
var $class;
var $table;
function LFPDataFactory($args) {
$this->unpackArgs($args); // assigns locals from $args
if (in_array(strtolower($this->class), get_declared_classes())) {
$this->object = new $this->class;
// assemble the columns in the table...
// select their values and put them in our new object...
} else { trigger_error("Class ".$this->class." not found", E_USER_ERROR); }
}
}
$r = new LFPDataFactory("class=LFPLayout,table=layout");
$new_obj = $r->object; // this is a LFPLayout object.
print_r($new_obj);
This class looks to see if the class exists, then instantiates it -- a declared class is not the same as an instantiated class. As long as LFPLayout exists somewhere in the scripts, get_declared_classes() will find it. Remember strtolower on compare, however.
Why would I do this? Because I have my class layouts the same as their respective tables; the factory then selects the data (making sure that the variables match) and plugs in the data. (I've left out the actual code to do the selection/insertion).
10-Jun-2004 09:46
// Useful function for determining if an object is either an
// instance or a subclass of a particular class.
function is_class($object,$class_name)
{
$parent = is_a($object, $class_name);
$child = is_subclass_of($object, $class_name);
return $parent xor $child;
}
29-May-2004 01:40
to pillepop2003
Why do u want to know the classname of an non-existant object?
The only possible explanation for this question seems to me u want to know the class before u instantiate the object. Well, this is of no use since u always instantiate a class of ur choice.
When the class is instantiated into an object u can find the class of the object by means of get_class(). This is all u need. In case of inheritance u can use get_class($this) to get the class of the instantiated object. Now u can differentiate according to which class the object belongs to.
e.g.:
<?php
class A{
function A(){
$class_of_this = get_class($this);
echo 'Object is an instance of class '.$class_of_this.' which is the ';
if(strcmp($class_of_this,'A')==0)
echo 'parent-class';
else if(strcmp($class_of_this,'B')==0)
echo 'child-class';
echo ".\n";
}
}
class B extends A{
function B(){
$this->A();
}
}
$object1 = new A();
$object2 = new B();
?>
When u run this code-snippet the output will be:
Object is an instance of class A which is the parent-class.
Object is an instance of class B which is the child-class.
02-Apr-2004 10:18
<?php
class calculator {
var $c;
function addition($a, $b) {
$this->c = $a + $b;
return $this->c;
}
function subtraction($a, $b) {
$this->c = $a - $b;
return $this->c;
}
function multiplication($a, $b) {
$this->c = $a * $b;
return $this->c;
}
function division($a, $b) {
$this->c = $a / $b;
return $this->c;
}
}
$cc = new calculator;
echo $cc->addition(20, 10)."<br>";
echo $cc->subtraction(20, 10)."<br>";
echo $cc->multiplication(20, 10)."<br>";
echo $cc->division(20, 10)."<br>";
?>
28-Aug-2003 11:59
I missed some kind of function to dynamicly override or extend an Object:
-----------------------------------------
function &extendObj(&$obj, $code) {
static $num = 0;
$classname = get_class($obj);
$newclass = $classname.$num;
eval('class '.$newclass.' extends '.$classname.' { '.$code.' }');
$newobj = new $newclass();
$vars = get_class_vars($classname);
foreach($vars AS $key=>$value) {
$newobj->$key = &$obj->$key;
}
return $newobj;
}
-----------------------------------------
This creates a new class which extends the old one by the given code parameter, instanciates it and copy all vars from the old obj to the new one.
-----------------------------------------
class testA {
var $prop = 'a';
function funcA($val) {
$this->prop = $val;
}
function value() {
return $this->prop;
}
}
$obj = new testA();
$newobj = &extendObj(&$obj, 'function addX() { $this->prop .= "x"; }');
$newobj->funcA('abc');
$newobj->addX();
echo $newobj->value();
-----------------------------------------
Results in 'abcx'. You can use the function multiple times and also with class variables. Be carefull, even if $newobj is just a copy of $obj, $obj->value() will return 'abcx', too, because of the & operator: $newobj->$key = &$obj->$key;
08-Jul-2003 09:24
FYI: if you want to split your class into manageble chunks, what means different files for you, you can put you functoins into includes, and make include() have a return value. Like this:
class Some_class {
var $value = 3;
function add_value ($input_param) {
return include ("path/some_file.php");
}
}
And your included file:
$input_param += $this->value;
return $input_param;
Then your function call will be:
$instance = new Some_class ();
$instance->add_value (3);
And this will return
6
hopefully :P
Keep in mind though, that the scope in the included file will be identical to the scope the function 'add_value' has.
And if you want to return the outcome, you should also have a return statement made in your include as well.
21-Sep-2002 06:52
Something I found out just now that comes in very handy for my current project:
it is possible to have a class override itself in any method ( including the constructor ) like this:
class a {
..function ha ( ) {
....if ( $some_expr ) {
......$this = new b;
......return $this->ha ( );
....}
....return $something;
..}
}
in this case assuming that class b is already defined and also has the method ha ( )
note that the code after the statement to override itself is still executed but now applies to the new class
i did not find any information about this behaviour anywhere, so i have no clue wether this is supposed to be like this and if it might change... but it opens a few possibilities in flexible scripting!!
15-Sep-2002 04:35
You may find it helpful in complex projects to have namespaces for your classes, and arrange these in a hierarchical manner. A simple way to do this is to use the filesystem to order your hierarchies and then define a function like this:
function use_namespace($namespace){
require_once("namespaces/$namespace.obj.php");
}
(lack of indentation due to HTML UI for this page)
This requires that all your object libraries end in .obj.php (which I use) but you can modfy it to suit your needs. To call it you could, for exmaple call:
use_namespace("example");
or if foo is part of example you can call:
use_namespace("example/foo");
20-Aug-2002 01:38
If you want to be able to call an instance of a class from within another class, all you need to do is store a reference to the external class as a property of the local class (can use the constructor to pass this to the class), then call the external method like this:
$this->classref->memberfunction($vars);
or if the double '->' is too freaky for you, how about:
$ref=&$this->classref;
$ref->memberfunction($vars);
This is handy if you write something like a general SQL class that you want member functions in other classes to be able to use, but want to keep namespaces separate. Hope that helps someone.
Justin
Example:
<?php
class class1 {
function test($var) {
$result = $var + 2;
return $result;
}
}
class class2{
var $ref_to_class=''; # to be pointer to other class
function class1(&$ref){ #constructor
$this->ref_to_class=$ref; #save ref to other class as property of this class
}
function test2($var){
$val = $this->ref_to_class->test($var); #call other class using ref
return $val;
}
}
$obj1=new class1;
# obj1 is instantiated.
$obj2=new class2($obj1);
# pass ref to obj1 when instantiating obj2
$var=5;
$result=obj2->test2($var);
# call method in obj2, which calls method in obj1
echo ($result);
?>
29-Sep-2001 02:10
I spent 20 minutes or so trying to figure this out, maybe someone else has the same problem.
To access a class' function from within the class you would have to say $this->functionname(params), rather than just functionname(params) like in other programming languages.
Hope this helps
08-Mar-2001 06:59
[Editor's note: If you are trying to do overriding, then you can just interrogate (perhaps in the method itself) about what class (get_class()) the object belongs to, or if it is a subclass of a particular root class.
You can alway refer to the parent overriden method, see the "Classes and Objects" page of the manual and comments/editor's notes therein.]
There is no function to determine if a member belongs to a base class or current class eg:
class foo {
function foo () { }
function a () { }
}
class bar extends foo {
function bar () { }
function a () { }
}
lala = new Bar();
------------------
how do we find programmatically if member a now belongs to class Bar or Foo.