John Sherwood says:
or you could use
mysql_select("SELECT UNIX_TIMESTAMP(fieldname) FROM tablename"), which would give you the date in seconds since unix epoch, and which you could compare to time().
However the datetime on the database server may not exactly match the datetime on the machine executing the PHP script.
Maybe better to get both at the same time - eg:
mysql_select("SELECT UNIX_TIMESTAMP(fieldname) AS `a`, UNIX_TIMESTAMP() AS `b` FROM tablename")
getdate
(PHP 4, PHP 5)
getdate — 日付/時刻情報を取得する
説明
array getdate
([ int $timestamp
] )
timestamp に関する日付情報を有する連想配列を返します。 timestamp が指定されない場合は、現在のローカルな時間に関する情報を返します。
パラメータ
返り値
timestamp に関連する情報を連想配列で返します。 返される連想配列の内容は、次のようになります。
| キー | 説明 | 戻り値の例 |
|---|---|---|
| "seconds" | 秒。数値。 | 0 から 59 |
| "minutes" | 分。数値。 | 0 から 59 |
| "hours" | 時。数値 | 0 から 23 |
| "mday" | 月単位の日。数値 | 1 から 31 |
| "wday" | 曜日。数値。 | 0 (日曜) から 6 (土曜) |
| "mon" | 月。数値。 | 1 から 12 |
| "year" | 年。4桁の数値。 | 例: 1999 あるいは 2003 |
| "yday" | 年単位の日。数値。 | 0 から 365 |
| "weekday" | 曜日。フルスペルの文字。 | Sunday から Saturday |
| "month" | 月。フルスペルの文字。 | January から December |
| 0 | UNIX時（1970年1月1日）からの秒数。 time()の戻り値と同様。 date()でも使用される。 | システムによって違うが、通常は-2147483648 から 2147483647. |
例
例1 getdate() の例
<?php
$today = getdate();
print_r($today);
?>
上の例の出力は、たとえば 以下のようになります。
Array ( [seconds] => 40 [minutes] => 58 [hours] => 21 [mday] => 17 [wday] => 2 [mon] => 6 [year] => 2003 [yday] => 167 [weekday] => Tuesday [month] => June [0] => 1055901520 )
getdate
Anonymous
05-Apr-2008 12:38
05-Apr-2008 12:38
Chris
27-Mar-2008 01:54
27-Mar-2008 01:54
This function by John Sherwood does the opposite:
function pastdate($t)
{
if (strtotime($t) < time())
return false;
return true;
}
When the current time has passed $t it ought to be true.
The correct answer can be given by this simple 1-liner:
function pastdate($t)
{
return (strtotime($t) < time());
}
timforte at gmail dot com
11-Jan-2008 01:07
11-Jan-2008 01:07
It's worth noting that this is local time, not UTC/GMT - gmgetdate doesn't exist :(.
The most logical way to handle date arithmetic without hitting DST problems is to work in UTC...
function add_days($my_date,$numdays) {
$date_t = strtotime($my_date.' UTC');
return gmdate('Y-m-d',$date_t + ($numdays*86400));
}
[it's even faster if you use gmmktime instead of strtotime]
Nick Reale
13-Apr-2007 12:15
13-Apr-2007 12:15
Anyone Interested in Generating dates for week, last week, month, last month, quarter, last quarter, YTD, Last YTD, Last Year can use this simple code.
It defaults to the date format YYYY-MM-DD but you can adjust it in the script.
<?
$t=getdate();
$today=date('Y-m-d',$t[0]);
//This Week//
$start=$t[0]-(86400*$t[wday]);
$twstart=date('Y-m-d',$start);
//Last Week//
$lwstart=$start-604800;
$lwend=$lwstart+518400;
$lwstart=date('Y-m-d',$lwstart);
$lwend=date('Y-m-d',$lwend);
//This Month//
$tmstart="$t[year]-$t[mon]-01";
//Last Month//
if($t[mon]=="1"){
$lmstart="2007-12-01";
}
else {
$lmstart="$t[year]-".($t[mon]-1)."-01";
}
$lmmonth=($t[mon]-1);
if($lmmonth=="4" OR $lmmonth=="5" OR $lmmonth=="9" OR $lmmonth=="11"){
$lmend="$t[year]-$lmmonth-30";
}
elseif($t[mon]=="2"){
$lmend="$t[year]-$lmmonth-28";
}
else {
$lmend="$t[year]-$lmmonth-31";
}
//This Quarter//
if($t[mon]=="1" OR $t[mon]=="2" OR $t[mon]=="3"){
$tqstart="$t[year]-01-01";
$tqend="$t[year]-03-31";
}
elseif($t[mon]=="4" OR $t[mon]=="5" OR $t[mon]=="6"){
$tqstart="$t[year]-04-01";
$tqend="$t[year]-06-30";
}
elseif($t[mon]=="7" OR $t[mon]=="8" OR $t[mon]=="9"){
$tqstart="$t[year]-07-01";
$tqend="$t[year]-09-30";
}
else {
$tqstart="$t[year]-10-01";
$tqend="$t[year]-12-31";
}
//Last Quarter//
if($t[mon]=="1" OR $t[mon]=="2" OR $t[mon]=="3"){
$lwstart=($t[year]-1)."-10-01";
$lwend=($t[year]-1)."-12-31";
}
elseif($t[mon]=="4" OR $t[mon]=="5" OR $t[mon]=="6") {
$lqstart="$t[year]-01-01";
$lqend="$t[year]-03-31";
}
elseif($t[mon]=="7" OR $t[mon]=="8" OR $t[mon]=="9"){
$lqstart="$t[year]-04-01";
$lqend="$t[year]-06-30";
}
else {
$lqstart="$t[year]-07-01";
$lqend="$t[year]-09-30";
}
//Year To Date//
$ystart="$t[year]-01-01";
//Last Year To Same Date//
$lystart=($t[year]-1)."-01-01";
$lytend=($t[0]-31536000);
$lytend=date('Y-m-d',$lytend);
//Last Year//
$lyend=($t[year]-1)."-12-31";
echo "This Week<br>Start $twstart<br>Finish $today<br><br>";
echo "Last Week<br>Start $lwstart<br>Finish $lwend<br><br>";
echo "This Month<br>Start $tmstart<br>Finish $today<br><br>";
echo "Last Month<br>Start $lmstart<br>Finish $lmend<br><br>";
echo "This Quarter<br>Start $tqstart<br>Finish $today<br><br>";
echo "Last Quarter<br>Start $lqstart<br>Finish $lqend<br><br>";
echo "Year To Date<br>Start $ystart<br>Finish $today<br><br>";
echo "Last Year To Date<br>Start $lystart<br>Finish $lytend<br><br>";
echo "Last Year<br>Start $lystart<br>Finish $lyend<br><br>";
?>
andre at anlex dot co dot za
13-Dec-2006 09:38
13-Dec-2006 09:38
I thought best to show a posseble way to go about bypassing the end month issue where the first day in a new month will have the monday of the week that it falls in - in the old month. Use the numbering of days as the constant and work you way from there.
Example:
<?php
//-----------------------------
$now = time();
$num = date("w");
if ($num == 0)
{ $sub = 6; }
else { $sub = ($num-1); }
$WeekMon = mktime(0, 0, 0, date("m", $now) , date("d", $now)-$sub, date("Y", $now)); //monday week begin calculation
$todayh = getdate($WeekMon); //monday week begin reconvert
$d = $todayh[mday];
$m = $todayh[mon];
$y = $todayh[year];
echo "$d-$m-$y"; //getdate converted day
?>
Allot less code makes everyone happy..
Jared Armstrong
10-Dec-2006 03:05
10-Dec-2006 03:05
A nice little function I wrote to determine what number occurrence weekday it is of the month for a given timestamp. (I.e. 2nd Friday, or the 3rd Thursday)
Eg: print_r(getWeekdayOccurrence(mktime(0, 0, 0, 12, 1, 2006)));
Outputs: Array ( [0] => 1 [1] => Friday ) [The first friday]
Eg. print_r(getWeekdayOccurrence(mktime(0, 0, 0, 8, 17, 2009)));
Outputs: Array ( [0] => 3 [1] => Monday ) [The third Monday]
function getWeekdayOccurrence($time) {
$month = intval(date("m", $time)); $day = intval(date("d", $time));
for ($i = 0; $i < 7; $i++) {
$days[] = date("l", mktime(0, 0, 0, $month, ($i+1), date("Y", $time)));
}
$posd = array_search(date("l", $time), $days);
$posdm = array_search($days[0], $days) - $posd; /
return array((($day+$posdm+6)/7), $days[$posd]);
}
cesar at nixar dot org
23-Oct-2006 12:49
23-Oct-2006 12:49
<?php
/**
* This function is similar to getdate() but it returns
* the month information.
*
* Returns an associative array containing the month
* information of the parameters, or the current month
* if no parameters are given.
*
*/
function getmonth ($month = null, $year = null)
{
// The current month is used if none is supplied.
if (is_null($month))
$month = date('n');
// The current year is used if none is supplied.
if (is_null($year))
$year = date('Y');
// Verifying if the month exist
if (!checkdate($month, 1, $year))
return null;
// Calculating the days of the month
$first_of_month = mktime(0, 0, 0, $month, 1, $year);
$days_in_month = date('t', $first_of_month);
$last_of_month = mktime(0, 0, 0, $month, $days_in_month, $year);
$m = array();
$m['first_mday'] = 1;
$m['first_wday'] = date('w', $first_of_month);
$m['first_weekday'] = strftime('%A', $first_of_month);
$m['first_yday'] = date('z', $first_of_month);
$m['first_week'] = date('W', $first_of_month);
$m['last_mday'] = $days_in_month;
$m['last_wday'] = date('w', $last_of_month);
$m['last_weekday'] = strftime('%A', $last_of_month);
$m['last_yday'] = date('z', $last_of_month);
$m['last_week'] = date('W', $last_of_month);
$m['mon'] = $month;
$m['month'] = strftime('%B', $first_of_month);
$m['year'] = $year;
return $m;
}
// Output
print_r(getmonth(11, 1978));
print_r(getmonth());
?>
John Sherwood
15-May-2006 03:10
15-May-2006 03:10
In response to the "Simple routine for determining whether a date in mySQL format has gone past":
function pastdate($t)
{
if (strtotime($t) < time())
return false;
return true;
}
or you could use
mysql_select("SELECT UNIX_TIMESTAMP(fieldname) FROM tablename"), which would give you the date in seconds since unix epoch, and which you could compare to time().
Cas_AT_NUY_DOT_INFO
04-Mar-2006 10:47
04-Mar-2006 10:47
// This functions calculates the next date only using business days
// 2 parameters, the startdate and the number of businessdays to add
function calcduedate($datecalc,$duedays) {
$i = 1;
while ($i <= $duedays) {
$datecalc += 86400; // Add a day.
$date_info = getdate( $datecalc );
if (($date_info["wday"] == 0) or ($date_info["wday"] == 6) ) {
$datecalc += 86400; // Add a day.
continue;
}
$i++;
}
return $datecalc ;
}
leo25in at yahoo dot com
11-May-2005 09:17
11-May-2005 09:17
getting weekday(actual date) from any give date.
function cal_date($wday,$tstamp)
{
return $tstamp-($wday*(24*3600));
}
function getweekday($m,$d,$y)
{
$tstamp=mktime(0,0,0,$m,$d,$y);
$Tdate = getdate($tstamp);
$wday=$Tdate["wday"];
switch($wday)
{
case 0;
$wstamp=cal_date($wday,$tstamp);
//echo date("Y-m-d",$wstamp);
break;
case 1;
$wstamp=cal_date($wday,$tstamp);
//echo date("Y-m-d",$wstamp);
break;
case 2;
$wstamp=cal_date($wday,$tstamp);
//echo date("Y-m-d",$wstamp);
break;
case 3;
$wstamp=cal_date($wday,$tstamp);
//echo date("Y-m-d",$wstamp);
break;
case 4;
$wstamp=cal_date($wday,$tstamp);
//echo date("Y-m-d",$wstamp);
break;
case 5;
$wstamp=cal_date($wday,$tstamp);
//echo date("Y-m-d",$wstamp);
break;
case 6;
$wstamp=cal_date($wday,$tstamp);
//echo date("Y-m-d",$wstamp);
break;
}
$w["day"]=date("d",$wstamp);
$w["month"]=date("m",$wstamp);
$w["year"]=date("Y",$wstamp);
return $w;
}
Liis make
16-Sep-2004 07:22
16-Sep-2004 07:22
function win2unix($date_string,$date_timestamp)
{
$epoch_diff = 11644473600; // difference 1601<>1970 in seconds. see reference URL
$date_timestamp = $date_timestamp * 0.0000001;
$unix_timestamp = $date_timestamp - $epoch_diff;
echo date($date_string,$unix_timestamp);
}
getisomonday($year, $week)
22-Apr-2004 06:58
22-Apr-2004 06:58
getdate does not convert week numbers. this function relies on strftime to find a timestamp that falls on the monday of specified year and ISO week:
<?php function getisomonday($year, $week) {
# check input
$year = min ($year, 2038); $year = max ($year, 1970);
$week = min ($week, 53); $week = max ($week, 1);
# make a guess
$monday = mktime (1,1,1,1,7*$week,$year);
# count down to week
while (strftime('%V', $monday) != $week)
$monday -= 60*60*24*7;
# count down to monday
while (strftime('%u', $monday) != 1)
$monday -= 60*60*24;
# got it
return $monday;
} ?>
Yura Pylypenko (plyrvt at mail dot ru)
15-Sep-2003 10:29
15-Sep-2003 10:29
In addition to canby23 at ms19 post:
It's a very bad idea to consider day having 24 hours (86400 secs), because some days have 23, some - 25 hours due to daylight saving changes. Using of mkdate() and strtotime() is always preferred. strtotime() also has a very nice behaviour of datetime manipulations:
<?php
echo strtotime ("+1 day"), "\n";
echo strtotime ("+1 week"), "\n";
echo strtotime ("+1 week 2 days 4 hours 2 seconds"), "\n";
echo strtotime ("next Thursday"), "\n";
echo strtotime ("last Monday"), "\n";
?>
intronis
12-Sep-2003 03:04
12-Sep-2003 03:04
When adding a timestamp to a database from php, be carefule because if your DB Server is a different computer than your webserver, the NOW() function in the SQL will use the DB Server's time, and not the web server's. You can use NTP to synch the times on both computers.
logan dot hall at asu dot edu
12-Mar-2002 05:32
12-Mar-2002 05:32
It seems that 'yday' (the day of the year) that php produces is one less than what the unix 'date +%j' produces.
Not sure why this is, but I would guess that php uses 0-365 rather than 1-366 like unix does. Just something to be careful of.
ih2 at morton-fraser dot com
17-Oct-2000 09:01
17-Oct-2000 09:01
To do comparisons on dates stored in mysql db against 7 days ago, 1 month ago etc use the following:
$last_week = date("Y-m-d", mktime(0,0,0, date(m), date(d)-7,date(Y)));
if($date > $last_week)
{
etc.
This allows for intelligent looping i.e. works at start/end of month/year
I have noticed other postings re this and they have not worked for me.Hope this helps.