JPS5822716B2 - hairspring spring - Google Patents

Description

[Detailed description of the invention] The present invention relates to a balance spring adjusting device.

Conventionally, the following devices have been used to adjust the frequency of the balance wheel and cut the hairspring.

The vibration output of the balance wheel is extracted and its frequency is multiplied to drive the motor.

On the other hand, the output from the crystal oscillator is frequency-divided to a predetermined value, thereby driving another motor, and both motors rotate the differential gear.

Then, the hairspring is fed by the rotation of a disk fixed to the shaft of this differential gear, and when the rotation speeds of both motors match, that is, when the operator confirms that the disk has stopped, the switch of the cutting device is operated to move the hairspring. disconnect.

This method has the disadvantage that the operator must constantly check whether the disk has stopped, and is inconvenient because most of the work is done by mechanical mechanisms, which increases the number of motors and makes the overall structure larger. there were.

Therefore, the present invention eliminates the above-mentioned drawbacks by converting most of the mechanism into electronic circuits and automatically adjusting and cutting the hairspring.

An embodiment of the present invention will be described below based on the drawings.

In this embodiment, the vibration period of the balance wheel to be adjusted, which has a maximum daily difference of 6000 seconds, is detected, and the vibration period of the balance wheel is adjusted to 0.4 seconds.

FIGS. 1 and 2 show a balance, a detection coil, and a drive coil.

1 is a shaft, 2 is a large ring fixed to the shaft 1, and 3 is a permanent magnet fixed to the large ring 2.

Reference numeral 4 denotes a hairspring with one end fixed to the shaft 1, and the other end 4a fixed to the outside.

5 is a coil. In FIG. 3, A is a balance drive circuit, B is an amplification and waveform shaping circuit, and D is a conversion circuit.

67...10, 10a are resistors, 11 is a capacitor, and 12 is a DC power supply.

13 and 14 are a detection coil and a drive coil, respectively.

15 and 16 are transistors, 17 is a diode, and 18 is an operational amplifier.

19, 20.21 are gate circuits, 22.23 are inverters, and 24, 25, 26.27 are flip-flop circuits.

28 is a manual switch, 29, 30.31 are each 30
There are six one-shot pulse generators of microseconds, 3 seconds, and 0.15 seconds.

In Fig. 4, 32, 33...39 are one-shot pulse generators, 40 is a frequency divider, 41°42...
...48 is a decimal counter.

49 is an IMHz clock pulse generator, and 50 is ×.

This is a p frequency division stage. 5L 52, 53, 54 are latch circuits, 55, 56, 57 are 10's complement circuits, 58.59.6
0 is a flip-flop circuit 661.62...
...112 is a gate circuit, 113°114...
138 is an inverter.

139 is a one-shot pulse generator with a delay function.

Reference numeral 140 denotes a drive circuit for a four-phase two-excitation motor M, which is an adjusting device for winding or rewinding the hairspring.

141 is a matching circuit, and 142 and 143 are completely similar circuits.

144 is a selection circuit, and 145 is a circuit completely similar to this.

146 is a manual switch for resetting.

Next, the operation will be explained based on FIGS. 3 and 4 while referring to FIG. 5.

First, one end 4a of the hairspring of the balance to be adjusted is held between the roller F shown in the fifth figure, which rotates in conjunction with the motor M, and the shaft F, and then the balance spring shown in the third figure.

The switch 28 is closed.

As a result, the terminal d shown in FIG. 4 is inverted to a low level, and the output of the gate circuit 107 is inverted to a high level.

Therefore, the output of the inverter 137 is at a low level, the output of the gate circuit 98 is at a high level, the output of the inverter 133 is at a low level, and the output of the inverter 134 is at a high level, and the single power of the gate circuits 103, 104, and 111 is maintained at a high level. do.

On the other hand, since the output of the inverter 136 is also held at a high level, the output pulse of the frequency dividing stage 50 is supplied to the gate circuit 110 via the gate circuit 109.

At this time, since the output Q of the one-shot pulse generator 139 is held at a low level, the output of the gate circuit 10.8 is held at a high level.

Therefore, the output pulse of gate circuit 109 is supplied to gate circuit 99.degree. 103 via gate circuit 110, inverter 138 and gate circuit 112.

Therefore, the output of the gate circuits 101 and 105 includes a frequency dividing stage 5.
Pulses with the same period as the output pulse of 0 are generated in opposite phases to each other.

Therefore, depending on the phase of the first pulse supplied to the flip-flop circuits 59 and 60, the flip-flop circuits 59 and 60
output Q of the flip-flop circuit 60, output Q of the flip-flop circuit 59, output Q1 of the flip-flop circuit 60
Pulses are generated that are shifted by an A period in the order of Q, or pulses that are shifted by a hip period in the reverse order.

However, since the power of the switching gate circuit 111 is maintained at a high level, the output Q of the flip-flop circuit 59
One-shot pulse generator 39 generated by the falling edge of
The pulse of the output Q resets the flip-flop circuit 60 via the gate circuit 111.

Therefore, the outputs Q and Q of the flip-flop circuits 59 and 60
The pulses are generated in the former order and actuate the drive circuit 140, driving the motor and winding the hairspring.

After winding it up to a suitable position, the switch 28 is opened.

Then, the balance is caused to vibrate by the drive circuit A.

When the switch 28 is opened, the output of the inverter 22 is inverted to a low level, and the outputs Q and Q of the one-shot pulse generator 30 are inverted to a high level and a low level, respectively.

On the other hand, the output to the drive circuit is supplied to the one-shot pulse generator 29 via the amplification and waveform shaping circuit B.

The one-shot pulse generator 290 output Q has a pulse width of 3
A 0 μs pulse is generated and supplied to the gate circuit 19.

On the other hand, due to the inversion of the level of the output Q of the one-shot pulse generator 30, the flip-flop circuit 580 shown in FIG.
The input is inverted to a high level, and the inverted signal of the output Q of the one-shot pulse generator 30 is further inverted via the gate circuit 65 and supplied to the T input of the flip-flop circuit 58.

As a result, the output Q of the flip-flop circuit 58 is inverted to a high level.

Therefore, although the input terminal of the gate circuit 190 shown in FIG. 3 is held at a high level, the one-shot pulse generator 3
Since the output Q of 0 is held at a low level, the gate circuit 19 is closed for the set time of the one-shot pulse generator 30 for 3 seconds.

This is to prevent the output of the one-shot pulse generator 29 from passing through for a sufficient period of time for the vibration of the balance to stabilize, which is 3 seconds in this embodiment.

Then, after 3 seconds have elapsed, the output Q of the one-shot pulse generator 30 is inverted to high level, the gate circuit 19 is opened, and the output pulse of the one-shot pulse generator 29 is supplied to the gate circuit 20 via the gate circuit 19. .

Since the one-shot pulse generator 31 is in the reset state, its output Q is at a high level, and the output pulse of the gate circuit 19 is passed through the gate circuit 20 and the inverter 23 to the flip-flop circuit 24 and the one-shot pulse generator 31. The output Q is inverted to a low level by the fall of the output pulse of the inverter 23, and the gate circuit 20 is closed for 0.15 seconds.

This is due to the following reasons.

When the balance wheel is driven by a drive circuit, the positions of the coil 5 and the permanent magnet 3 are shifted each time, and the number of times the permanent magnet 3 passes the coil 5 during one cycle of vibration differs due to this shift.

However, only two pulses are required to detect the vibration period of the balance wheel, and other unnecessary signals must be prevented from passing through.

This will be explained below.

Figures 6A, B, and C show a one-shot pulse generator 29 and a one-shot pulse generator 3, respectively, when the permanent magnet 3 passes over the coil 5 twice during one period of vibration of the balance wheel.
1 and the outputs of inverter 23 are shown.

In this case, since no unnecessary pulses are generated during one vibration of the balance, the output pulses of the one-shot pulse generator 29 can be supplied as they are to the flip-flop circuit via the gate circuit 20 and the inverter 23.

Figures 7A, B, and C show a one-shot pulse generator 29 when the permanent magnet 3 passes through the coil 5 three times during one period T.
, one-shot pulse generator 31 and inverter 23
This shows the output of

In this case, a pulse P1 is generated during one vibration, which causes a timing error.

Since this is blocked from passing by the pulse shown in Figure 7B, two pulses are generated during one period T at the output of the inverter 23.

7D and 7E show the outputs of the one-shot pulse generator 31 and the inverter 23 when the one-shot pulse generator 30 operates immediately after the pulse Pa shown in FIG. 7A is generated.

In this case, the first three pulse intervals t are different from the vibration period T, but from the next pulse onward, pulses are generated at normal periods.

FIG. 8 shows a case where the light passes four times during one period T.

Among the outputs of the one-shot pulse generator 29 shown in FIG. 8A, pulses P2 and P3 are unnecessary, and the output Q of the one-shot pulse generator 31 shown in FIG.
゜Prevent the passage of P3.

Therefore, a pulse is generated at the output of the inverter 23 as shown in FIG.

8D and 8E show the outputs of the one-shot pulse generator 31 and the inverter 23 when the one-shot pulse generator 30 operates immediately after the pulse pb shown in FIG. 8A is generated.

In this case as well, the first three pulse intervals t' are different from the period T, but from the next pulse onward, pulses are generated at normal periods.

As described above, even if the number of times the coil 5 passes through the permanent magnet 3 differs depending on the starting position of the balance, the gate circuit 20 is controlled by the output of the one-shot pulse generator 31 to prevent unnecessary pulses from passing. Therefore, only two pulses are supplied to the flip-flop circuit 24 within one period of vibration of the balance, and the vibration period of the balance is determined from these pulses.

Therefore, the output Q of the flip-flop circuit 24 generates a pulse whose period corresponds to one period T of the balance vibration, and this pulse is generated by the following flip-flop circuit 25.26.2.
The frequency is sequentially divided by 7.

Therefore, a pulse is generated at the output terminal C of the gate circuit 21, with one cycle being eight cycles of the vibration of the balance, and a pulse width being one cycle T of the vibration of the balance.

□This pulse is generated by the one-shot pulse generator 3 shown in Figure 4.
2.34 and the gate circuit 61.

Therefore, pulses are generated at the outputs Q and Q of the one-shot pulse generators 32 and 34, respectively.

On the other hand, the 250 KHz clock pulse from the frequency divider 40 is applied to the gate circuit 61 while the pulse is generated at the output terminal C of the gate circuit 21, that is, during the vibration period T of the balance wheel.
is supplied to the counter 41 via.

Therefore, if the difference is within 6000 seconds per day; if the vibration period of the adjusting balance is 0.4 seconds or more, the gate circuit 61
More than 100,000 pulses and less than 106,000 pulses pass through, and the count content of the counter 45 becomes O.

In addition, when the vibration period is 0.4 seconds or less, the gate circuit 6
1 passes 99999 pulses or less, and the count content of the counter 45 becomes 9.

First, a case where the vibration period of the balance to be adjusted is 0.4 seconds or more will be described.

Counters 42, 43 and 44 are respectively 10th and 100th place.
Count the 1000th place, and the counter 45 of the 10000th place is 0"
Count.

At this time, since the output of the gate circuit 96 is at a low level and the output of the inverter 128 is at a high level, the gate circuit 6B,
69, 70, 77.78° 79 and similar gate circuits of selection circuit 145 are selected.

Thereafter, the falling edge of the one-shot pulse from the generator 34 causes the latch circuits 51, 52, 53, and 54 to read the count contents of the counters 42, 43, 44, and 45.

At the same time, the counters 46, 47, 48 are reset via terminal e.

At this time, the memory contents of the latch circuits 51, 52, 53 are transferred to the coincidence circuit 141 via the gate circuits 68, 69, 70, 74°75.76, gate circuits 77.78, 79.8384.85, and selection gate circuit 145, respectively. ,142,1
43, then one-shot pulse generator 32
The output Q of the one-shot pulse generator falls, and the output Q of the one-shot pulse generator
A pulse is generated.

The contents of the latch circuits 51, 52, 53 are now stored in the counter 4.
6. Since the count contents of 47 and 48 are different, match circuit 1
The outputs of 41, 142, and 143 are held at low level.

Therefore, the output of the gate circuit 93 is held at a high level,
Gate circuit 86 and gate circuit 94 are opened.

Therefore, the output pulse of the frequency dividing stage 50 is supplied to the counter 46 via the gate circuit 86,
゜ starts counting.

At the same time, the output pulse of frequency dividing stage 50 is supplied to gate circuit 106 via gate circuit 94 and inverter 135.

At this time, all outputs of the latch circuit 54 are at a low level, so the output of the gate circuit 96 is at a low level. Therefore, the output of the gate circuit 97 is held at a high level, and the power of the gate circuit 106 is held at a high level. ing.

Therefore, the output pulse of inverter 135 is supplied to gate circuit 112 via gate circuit 106.

On the other hand, since the terminal d of the third cause is held at a high level, the output of the inverter 136 shown in FIG. 4 is at a low level, and the output of the gate circuit 109 is held at a high level.

Further, since the output of the gate circuit 08 is also held at a high level, the output of the gate circuit 110 is held at a low level, and the output of the inverter 138 is held at a high level.

Therefore, the pulse from gate circuit 106 passes through gate circuit 112 to gate circuit 99 and gate circuit 103.
supplied to

At this time, since the output Q and terminal d of the one-shot pulse generator 139 are held at high level, the gate circuit 1
The output of the inverter 137 is held at a low level, and the output of the inverter 137 is held at a high level.

Further, since the output of the gate circuit 96 is at a low level, the output of the gate circuit 98 is at a high level, and the output of the inverter 133 is at a low level to maintain Berni.

Therefore, the power of the gate circuit 99 and the gate circuit 103 are maintained at a low level and a high level, respectively, and the pulse from the gate circuit 106 causes the drive circuit 1 to
40 is activated, the motor is driven, and the hairspring is wound up.

Then, the counts of the counters 46, 47, and 48 progress, and when the count contents match the stored contents of the latch circuits 5L, 52, and 53, the outputs of the coincidence circuits 14L, 142, and 143 all become high level, and the output of the gate circuit 93 becomes high level. Flip to low level.

Therefore, gate circuit 86 and gate circuit 94 are closed.

Therefore, the drive of the motor is stopped and the winding of the hairspring is finished.

After that, the pulse from the output Q of the one-shot pulse generator 32 falls, a pulse is generated from the output Q of the one-shot pulse generator 33, and this rise resets the counters 42, 43, 44, 45. do.

Thereafter, a pulse is supplied from the gate circuit 21 shown in the third figure to the terminal CK shown in the fourth figure, which is caused by the vibration of the balance wheel whose hairspring is wound as described above.

Then, the same operation as described above is repeated.

By repeating this operation, the length of the hairspring is adjusted, and the output pulses of the frequency divider 35 are transferred to the counters 41 and 4.
2...45 counts and when the count contents of the counters 43 and 44 reach °0'', the inverters 119 and 120
, 121° 122 and inverter 129, 130, 1
The outputs of 31.degree. 132 all go to high level, and the outputs of gate circuits 67.92 go to low level.

Therefore, the outputs of the inverters 113 and 123 are held at a high level, and at this time, the output of the gate circuit 97 is held at a high level, and the output of the gate circuit 63 is held at a high level.

On the other hand, the outputs Q and Q of the one-shot pulse generator 32 are inverted from the outputs of the matching circuits 14L and 142 to high level, and after the motor stops, are inverted to low level and then high level, so the one-shot pulse generator A pulse is generated at the output Q of 33, and this fall causes the counters 42 and 4 to
? h, reset 4445.

Also, the output of gate circuit 62 is inverted to high level, and all inputs of gate circuit 630 are high level.

Therefore, the output of the gate circuit 63 is inverted to a low level,
As a result, the outputs Q and Q of the one-shot pulse generator 36
are inverted to high and low levels, respectively.

The reversal of the level of the output Q drives the rotary solenoid to cut the wound portion of the hairspring.

Furthermore, since the balance spring's vibration cycle is detected while the hairspring is being wound, the center of vibration is shifted, and short-term stability of the balance is also poor.

This causes an error.

Therefore, the count content of the counter 42 was set within this error range, and this count content was ignored.

On the other hand, due to the inversion of the output level, the output of the gate circuit 64 is inverted to a high level, and the output of the gate circuit 65 is inverted to a low level.

This generates a pulse at the output Q of the one-shot pulse generator 37; the fall of this pulse triggers the flip-flop circuit 58, and the output Q is inverted to a low level.

Therefore, the input terminal b of the gate circuit 19 shown in FIG. 3 is held at a low level, and the output pulse from the one-shot pulse generator 29 is cut off by the gate circuit 19.

On the other hand, due to the inversion of the level of the output σ of the flip-flop circuit 58, the output Q of the one-shot pulse generator 139
, Q is enough time for the balance spring to finish cutting,
In this embodiment, outputs Q and Q are each at a high level after a delay of 0.3 seconds.

Flip to low level.

Therefore, the output pulse of the frequency dividing stage 50 is transmitted to the gate circuit 108,
110. It is supplied to gate circuits 99 and 103 via inverter 138 and gate circuit 112.

At this time, the output of the gate circuit 107 is held at a high level.

The output of the inverter 137 is at a low level, and the gate circuit 98
The output of inverter 134 is held at a high level, and the output of inverter 134 is held at a high level.

Therefore, the output pulse of the gate circuit 106 causes the drive circuit 140 to operate in the same manner as described above to drive the motor.

Send out the severed part of Gezenmai and throw it away.

Next, a case where the vibration period of the balance wheel is 0.4 seconds or less will be explained.

In this case as well, the one-shot pulse generators 32, 33, and 34 are operated by the pulse generated at the terminal C in the same manner as described above.
The gate circuit 61 opens and the counter 4L 42...
45 starts counting.

However, since this pulse width is less than 0.4 seconds, it is supplied to the counter 41.

The number of output pulses of the frequency divider 40 must be 99999 or less.
The count content of the counter 45 becomes °゛9''.

Then, as described above, the count contents □ of the counters 42, 43, 44, 45 are read into the latch circuits 51, 52, 53, 54 by the fall of the output pulse of the one-shot pulse generator 34.

At the same time, counters 46, 47, 48 start counting.

At this time, since the content stored in the latch circuit 54 is 9'', the output of the gate circuit 96 becomes high level, and the output of the inverter 128 becomes low level.

Therefore, the gate circuit 71. γ273.80,81,82
and a similar gate circuit of the selection circuit 145 is selected,
The outputs of the complement circuits 55゜56.57 are respectively connected to gate circuits 71゜72.73, 74, 75, 76 and gate circuit 80.
81.82, 83, 84, 85 and selection gate circuit 1
45 to matching circuits 141, 142 and 143.

Note that the numerical value supplied to the coincidence circuits 141, 142143 must be the difference between 100000 and the count contents of the counters 41, 42, . . . , 45.

For this purpose, the 10's complement of the counts of the counters 42, 43, and 44 is taken and supplied to the coincidence circuits 141142 and 143.

At this time, since the output of the gate circuit 96 is at a high level, the output of the gate circuit 98 is at a low level, and the inverter 13
3, the output of the inverter 134 is held at a low level.

Therefore, contrary to the above, the inputs of the gate circuits 103 and 104 are held at a low level, and the inputs of the gate circuits 99, 100, and 102 are held at a high level. , Q are generated with a phase shift of A period, actuating the drive circuit 140 to rotate the motor in the opposite direction to that described above, and rewind the hairspring.

The following operations are performed in the same manner as described above.

If the error range of the adjusted balance wheel can be expanded somewhat compared to the above-mentioned embodiment, the complement circuits 55, 56, .
If the following circuit is used in place of 57, the circuit configuration can be simplified.

In Figure 9, 147 and 148 are "10" and "9" respectively.
149 is a circuit completely similar to the complement circuit 148.

150°151...161 is the gate circuit, 16
2,163...177 are inverters.

The same reference numerals as in FIG. 4 indicate the same parts.

With the circuit configuration described above, when the count content of the counter 42 is other than "0", the complement of the correct value is generated at the output of the complement circuits 147, 148 and 149.

When the count content of the counter 42 is “0”, the complement circuit 147
The output terminals f2g, h, and i all become low level, and
0'' occurs.

On the other hand, the complement circuit 148 receives "9", which is the count content of the counter 43.
The complement of is generated.

This takes into account the digits borrowed from the previous stage complement circuit 147, and calculates the complement of '9''. In this case, the complement circuit 1
Since there is no borrowing from 47, the complement of '10' must be generated correctly.

Further, when the count content of the counter 42 becomes "0", the output of the complement circuit 147 becomes "8".

Therefore, a value obtained by subtracting 20 from the correct error value is generated.

As detailed above, according to the present invention, the hairspring is adjusted and cut according to the time determined by the vibration output signal of the vibrating body, so everything from adjustment to cutting is done automatically. Does not require any manual labor.

In addition, the number of mechanical mechanisms is reduced and the size can be reduced.

[Brief explanation of drawings]

Fig. 1 is a front view of the balance, Fig. 2 is a plan view of the balance, Figs. 3 and 4 are circuit diagrams of an embodiment of the present invention, and Fig. 5 schematically shows the adjustment and cutting mechanism. Explanatory diagrams, Figures 6, 7 and 8 are time charts for illustration purposes only,
FIG. 9 is a circuit diagram of another embodiment of a part of the circuit of the present invention. A... Balance drive circuit, D... Detection circuit, 41°42.48... Counter, 61... Gate circuit, 86
...Gate circuit, 141, 142, 143... Matching circuit, M... Motor, E... Roller, 9... Cutting device.

Claims (1)

[Claims] 1 A vibrating body whose vibration period is determined by a hairspring is provided, a conversion circuit is provided to convert the vibration output signal of this vibrating body into a pulse according to the vibration period, and the passage of a clock pulse is controlled by the output pulse of this conversion circuit. a first counter for counting clock pulses passing through the control circuit; a second counter for counting reference pulses after the first counter finishes counting; A hairspring feeding device is provided to send a balance spring when the counter starts counting, and when the coincidence of the counts of the first counter and the second counter is detected, the counting of the second counter is stopped. A matching circuit is provided to stop the operation of the balance spring feeding device, and each of the above operations is repeated every time a pulse arrives from the conversion circuit until the count of the first counter reaches a preset count value. A hairspring adjustment device comprising: a control circuit for controlling the hairspring; and an operating circuit for activating a hairspring cutting device after the count of a first counter reaches a preset count value.