JPS6052993B2 - Automatic landing device during elevator power outage - Google Patents

Description

DETAILED DESCRIPTION OF THE INVENTION The present invention relates to an improvement in a device for automatically landing an elevator car on a floor during a power outage.

In the event of a power outage, the brake is applied when the elevator car reaches a predetermined speed or reaches the area where the door of each floor can be opened and closed (the area where the car door and the landing door can be engaged and opened and closed). An automatic floor landing device has been proposed in the event of an elevator power outage, which allows the elevator to travel to the floor by inertia.

Considering the safety of passengers, the area where the door can be opened and closed is normally ±15-200Wt from the landing level! Because the car is narrow, about R, if a power outage occurs while the car is running at the rated speed in the area where the door can be opened and closed on the nearest floor, it is often impossible to stop the car within the area where the door can be opened and closed. In particular, when the total weight on the car side is equal to the total weight on the counterweight side (hereinafter referred to as "balanced load"), or when the load is close to the balanced load, the car becomes unable to run and passengers are trapped inside the car ( There was a very high possibility that the situation would become ``clogged''. The above points will be explained with reference to FIG.

In Figure 1, at the normal landing level a, a1a2 is the section where the door can be opened and closed, × is the car speed curve that allows the car to brake at maximum load and stop at point a2 while ascending, B' is the straight line a, The intersection point of a' and the curve When traveling in the upward direction (hereinafter referred to as "lifting load release"), the brakes are released at point A and the brake is coasted.
When traveling in the direction of lowering either the total weight of the basket side or the total weight of the counterweight side, whichever is heavier (hereinafter referred to as the "lowering direction"), the brake is released at point A and the direction of acceleration is increased when coasting. It is. Generally, the curve × is the case where the braking is applied the strongest, so as is clear from Figure 1,
If the rated speed V3 is higher than the speed at point B'', it is impossible to stop within the door opening/closing area when the vehicle is traveling at the rated speed ■3 within the door opening/closing area?=.

If a power outage occurs at point z while driving at the rated speed Vs within the zone where the door can be opened and closed, the brakes will be applied and the vehicle will reach point 4. When the 4th point is reached, the brake is released and the elevator runs using its own energy.

14 is a case in which the car is traveling in the direction of unloading, and the car speed increases due to the unbalance between the car side and the counterweight side, so the car has enough energy to reach the section where the door of the next floor can be opened and closed.

However, when the car is traveling in the direction of lifting a load, the car speed decreases and finally stops at 4 points. If the amount of unbalance between the car side and the counterweight side is small, the elevator will be defeated by the static friction torque of the elevator, and reverse self-propulsion will become impossible. Particularly in geared elevators, we have obtained experimental results that if the load is no load or a load relatively close to the rated load, for example 20% load, reversal self-propulsion may become impossible.
In general, when coasting from the rated speed V with a load close to the balanced load, the coasting distance is quite long, and there is enough energy to travel between normal floors, but as mentioned above, the door can be opened and closed. section? Because braking is applied within the range, there is a large loss of energy, and the probability of jamming is extremely high. This invention solves the above-mentioned problem, and effectively utilizes the inertia energy retained while traveling at the rated speed within the section where the doors can be opened and closed, thereby minimizing the probability of passengers being stuck in a power outage. The purpose of this invention is to provide an automatic bed landing device.

An embodiment of the present invention will be described below with reference to FIGS. 2 to 5. Figure 2 is a setting diagram of the section where braking is applied by the brake (hereinafter referred to as 1 braking section), where Y is the car speed curve I so that the brake can be applied while descending with the maximum load and the car can be stopped at point A2, and B is the curve. Y and straight line? The intersection point with blue, Vbl, is the first predetermined speed, Vb, which is set slightly higher than the rated speed Vs in order to apply the brakes when the car speed is higher than this.
2 is the second predetermined speed set to the speed of point B, F is the point where the curve Y becomes the speed Vbl, A3 is a position slightly to the left of the distance of point F, and A, C, D, E indicates the apex of the braking zone set by their position and speed.

In the figure, the braking section is shown with diagonal lines. Third
The figure shows a case where the braking section shown in FIG. 2 is provided on each floor.

G-U is a point set similarly to the upper point of A. The part above the horizontal axis shows the speed in the direction of travel before the power outage, and the part below shows the speed in the opposite direction to the direction of travel before the power outage when the vehicle is reversed, similar to Figure 2. , the braking section is shown with diagonal lines. In Figure 4, 1 is a power failure detection relay,
1a to 1d are the normally open contacts, 1e and 1f are the normally closed contacts, J2 is the electromagnetic brake coil, 3a and 3b are the brake release condition contact group during normal power supply, and 4 is the brake for releasing the brake during power outage. With open relay, 4a, 4
b is the normally open contact, and 5 is the section where the door can be opened/closed? A mechanical contact group for detecting the heart, 6 is a door opening/closing section detection relay, 6a
is its normally closed contact, and 7 is the center of the predetermined section in Figures 1 and 2. 8 is a relay for detecting a predetermined section, 8a is a normally closed contact thereof, 9 is a first predetermined speed Vb
Normally open contacts 10a and 10b of a relay (not shown) that is deenergized when the speed exceeds Vb2 are normally open contacts and normally closed contacts of a relay (not shown) that is deenergized when the speed exceeds a second predetermined speed Vb2, N+ , N- are normal power supplies, and E+ and E- are storage battery power supplies.

Figure 5 shows the trajectory of the car speed when a power outage occurs while the car is running at the rated speed V: 3 in the area where the door can be opened and closed, and Wl, W3, W5, Xl, Y2, Y4 are Braking start point, W2, W4, Y3 are brake release points, W6, X2,
Y5 is the stopping point, and Y1 is the point where the speed is reversed.

Next, the operation of this embodiment will be explained.

If a power outage occurs at point Z while the car is traveling in the direction of unloading, relay 1 is deenergized, contacts 1a to 1d are opened, and contacts 1e and 1
f is closed.

Since the car is within the door opening/closing area Ala2, the contact group 5 is closed, the relay 6 is energized by the circuit (E+)-1e-5-6-1f-(E-), and the contact 6a is opened. At this time, the car speed is the rated speed V, and the contacts 9 and 10b are closed from the relationship Vbl>V,>Ab2. The basket is in the specified section =
Since there is no one between the centers, the relay 8 is deenergized and the contact 8a is closed, so (E+)-1e-9-10b-8a-4
The relay 4 is energized by the -1f-(E-) circuit, and the brake coil 2 is energized by the (E+)-1e-4a-2-4b-1f-(E-) circuit. , the brake remains open. Therefore, the car will coast, but the speed will increase due to the amount of imbalance between the car side and the counterweight side. Is there a section where the car door can be opened and closed? If = is removed, the relay 6 is deenergized, but the relay 4 remains energized by the circuit, and the brake release state continues.
When the car speed increases and becomes equal to or higher than Vbl, the contact 9 is opened and the relay 4 is deenergized, so the contacts 4a and 4b are opened and the brake coil 2 is deenergized and enters a braking state. However, in reality, it takes some time (hereinafter referred to as "immobility time") after the brake coil 2 is deenergized until the brake is applied, or after it is energized until it is released.
The point at which braking begins is point W1. When the brake is applied, the speed decreases, and when the speed drops to Vbl, the contact 9 closes again, so the relay 4 is energized again in the circuit described above, the brake coil 2 is energized, and the brake is activated after the brake is inactive. is released at the W2 point, so the car speed increases again. This process is repeated until the car reaches the braking section Dq. When the car reaches the braking section (3), the contact group 7 is closed, the relay 8 is energized, and the contact 8a is opened. On the other hand, since the car speed is Vb2 or higher, the contact 10a is open and the relay 4 is deenergized. Therefore, the brake coil 2 is deenergized and enters a braking state. When the car speed decreases to below Vb2,
Contact 10a is closed, (E+)-1e-9-6a-10
The relay 4 is energized in the circuit a-4-1f-(E-), energizing the brake coil 2, the brake is released, and the speed begins to increase again at point W. When the basket enters the area where the door can be opened and closed,
The relay 6 is energized by the circuit (E+)-1e-5-6-1f-(E-), and the contact 63a is opened. On the other hand, since the car speed is less than V■, the contact 10b is closed, so the relay 4 is deenergized, and the brake coil 2 is deenergized again to enter the braking state, and at point W6 within the door opening/closing area. Stop. In this case, the trajectory of the car speed is AllW2W3W
, W5W6. Next, if a power outage occurs at point z with a load close to the balanced load, the brake will remain open as in the case of traveling in the direction of unloading, but since the amount of unbalance between the car side and the counterweight side is small, , it coasts without slowing down much.

When the car enters the area where the door of the next floor can be opened and closed, braking is applied at point X1, similar to when the car is traveling in the unloading direction, and the car stops at point X2 within the area where the door can be opened and closed.
Next, when a power outage occurs at point Z while traveling in the lifting direction, the brake is released and the car coasts as described above, but due to the unbalance between the car side and the counterweight side, the car speed rapidly decreases.
Stop at point Y1. If the torque that attempts to move the car due to the amount of unbalance is greater than the static friction torque of the elevator, it reverses at point Y1 and begins to accelerate. Then, when reaching the braking section JK, the contact 10a is opened because the car speed is similar to Vb, as in the case of traveling in the unloading direction.
Further, since the contact point 8a is opened, the relay 4 is deenergized. Therefore, the brake coil 2 is deenergized and enters a braking state, and the speed of the car decreases. When the car speed decreases to below ■B2, the contact 10a closes and the relay 4 is energized to energize the brake coil 2, so the brake is released and the car speeds up again at point Y3. Is there a section where the car door can be opened and closed? = Repeat this until it goes inside. When the car enters the door opening/closing area, the relay 6 is energized and the contact 6a is opened, the relay 4 is deenergized, and the brake coil 2 is deenergized to maintain the braking state. In this way, the basket can be opened/closed section = Y5 in the heart.
Stop at a point. In this case, the trajectory of car speed is Δ1Y2Y
It is 3Y4Y5. In this way, when a power outage occurs while the vehicle is traveling at the rated speed V3 in the door opening/closing area (inside), if the vehicle is in the lifting direction, it can reverse and stop in the door opening/closing area of its own floor. In addition, since the speed is increased in the direction of unloading, the predetermined speed V
By applying the brakes after passing over the koji, the vehicle coasts at a speed close to the predetermined speed Vbl and comes to a stop within the area where the next floor door can be opened and closed. In addition, at a load close to balanced load,
The so-called normal floor spacing of about 3 to 47 TL has enough energy to run, so there is a high probability that the next floor will be able to stop in the area where the door can be opened and closed within the evening. The probability that the probability becomes extremely small can be reduced. In addition, in the example, a step-like braking section was provided such that the higher the car speed is, the more the brake is applied at 9 positions farther from the stopping floor, such as ACBE in FIGS. 3 and 5, It is clear that the same effect can be obtained by detecting speed and position in multiple stages and increasing the number of stages in the stepped control section.

If you make the step-like braking section infinitely finer and increase the number of steps,
It is also possible to obtain a braking section as shown in FIG. Also, the section in Figure 2? In =, the upper limit speed of the section in which the brakes are not applied is set to be the same as the first predetermined speed Vbl, but it may be set to a different speed. Similarly, given interval mind?
The lower limit speed was made the same as the second predetermined speed Vb2, but
Different speeds are also acceptable. In the conventional example, the predetermined speed at which braking is applied was set lower than the rated speed ■, so the door can be opened and closed at the rated speed V3? = When there was a power outage while driving outside, the brakes would be applied until the speed dropped below a predetermined speed, and some of the energy stored in the elevator would be lost. Since the predetermined speed Vbl of 1 is set to a value slightly higher than the rated speed V3, is it possible to open and close the door? Not only in the heart, but also in the area where the door can be opened and closed at the rated speed Vs =? Even if there is a power outage while the elevator is running outside, the energy held by the elevator can be utilized to the fullest without loss.

As explained above, in this invention, if a power outage occurs while the car is traveling within one section where the door can be opened and closed, the electromagnetic brake is prevented from operating if the car is running at a predetermined speed or higher, so the car is moved to the next floor. The possibility that the car will reach the section where the door can be opened and closed increases, and the probability that the car will stop between floors and passengers will be crammed together can be extremely reduced.

[Brief explanation of the drawing]

FIG. 1 is an explanatory diagram of the operation of a car by a conventional elevator automatic landing device during a power outage, and FIGS. 2 and 3 are braking section setting diagrams showing an embodiment of the elevator automatic flooring device during a power outage according to the present invention. , FIG. 4 is a circuit diagram thereof, FIG. 5 is an explanatory diagram of car operation, and FIG. 6 is a braking section setting diagram showing another embodiment of the present invention. 1 is a power failure detection relay, 2 is an electromagnetic brake coil, 3a,
3b is a brake release condition contact group during normal power supply, 4 is a brake release relay during power outage, 5 is a mechanical contact group for detecting a section where the door can be opened/closed, 6 is a relay for detecting a section where the door can be opened/closed, and 7 is a mechanical contact group for detecting a predetermined section. , 8 is a predetermined section detection relay, 9 is the first
10a, 10b are second predetermined speed detection relay contacts, N+, N- are normal power supplies, E+,
E- is a storage battery power source.

Claims (1)

[Claims] 1. An electromagnetic brake that brakes the electric motor for driving the elevator, a door openable zone detection device that detects when the elevator car enters a door openable zone set in the hoistway of the elevator, and a power source for the elevator. When the car is running at a speed higher than a predetermined speed set as a speed at which it can stop in the area where the door can be opened and closed when the power source is cut off and the electromagnetic brake is activated. a braking circuit that is connected to the storage battery power supply in the event of a power outage to operate the door opening/closable zone detection device and applies the electromagnetic brake when the predetermined speed detection device does not operate; When connected to the storage battery power supply, the electromagnetic brake is activated when either the door opening/closing area detecting device and the predetermined speed detecting device operate, or the door opening/closing area detecting device does not operate. An automatic landing device for an elevator during a power outage, comprising a brake release circuit that prevents running of the car due to inertial energy of the elevator.