JPH0219382B2 - - Google Patents

Description

DETAILED DESCRIPTION OF THE INVENTION <Industrial Application Field> The present invention relates to a method for setting the opening degree of an indoor air outlet in a so-called ductless air conditioning system in which a duct is removed from the ceiling.

<Conventional technology> Ductless air conditioning systems supply conditioned air from a blower to the space in the attic through an outlet in the ceiling, use the space in the attic as an air supply chamber, and supply conditioned air from an indoor outlet installed in the ceiling. It blows out conditioned air into the room. This ductless air conditioning system has the following advantages and is therefore widely used as an air conditioning system for large spaces such as large stores.

Since there is no duct work other than the main duct or insulation work, construction time can be shortened and construction costs can be reduced.

By significantly simplifying the ducts in the ceiling, the dimensions of the bottom end of the beam and the ceiling surface can be reduced compared to conventional duct systems, and the floor height can be reduced.

Since there is no connection between the main duct and the indoor air outlet, the indoor air outlet can be arranged freely. Therefore, flexibility in the design of the ceiling surface is ensured,
It will be easier to respond to remodeling after construction is completed. That is, flexibility in the arrangement of the indoor air outlet can be obtained.

Since the space under the attic is used as an air supply chamber, it is possible to utilize the radiation effect of the ceiling and floor surfaces and the heat storage effect of the floor surface, which has a large heat capacity.

However, in the ductless air conditioning system mentioned above,
For the following reason, the air volume from the indoor air outlet cannot be predicted, and the opening degree of the indoor air outlet must be set by trial and error by actually operating the indoor air outlet, which takes time and effort. There is a problem. That is, as shown in FIGS. 13 and 14, the blower 10
The conditioned air sent from 0 is air outlet 1 in the ceiling.
01, it is blown out into the space 102 in the attic, and convection occurs in the space 102 in the attic as shown by arrows A and B. Then, conditioned air is supplied from the space 102 under the attic to the air-conditioned room 115 through the indoor air outlets 103, 104, 105, and 106. By the way, the direction of flow of conditioned air shown by arrows A and B convecting in the space 102 under the attic, and the indoor air outlet 103,
Arrows X blown out from 104, 105, 106
There is a perpendicular relationship with the direction of air flow shown by arrows A and B, and the air flowing in convection shown by arrows A and B has a direction X of the indoor air outlet 103, 104, 105, and
has no velocity component. Therefore, the amount of air blown from the indoor air outlets 103, 104, 105, 106 is
It is determined by the static pressure difference between the inside and outside of the ceiling. On the other hand, according to Bernoulli's theorem, (dynamic pressure) + (static pressure) = 1 constant, so the static pressure distribution in the space 102 in the attic is determined by the flow velocity distribution of convection in the attic. However, the flow velocity distribution in the attic space is complicated and changes depending on the structure of the attic space, and it changes just by changing the opening degree of one indoor air outlet, so it is difficult to predict in practice.
Therefore, indoor air outlets 103, 104, 10
It is difficult to predict the air volume from 5,106.

For this reason, in the past, the opening degree of the indoor air outlet had to be set by trial and error using the actual machine, as described above, which posed the problem of requiring a lot of man-hours and time. Furthermore, since the amount of air from the indoor air outlet cannot be predicted, there is a problem in that the opening degree of the indoor air outlet cannot be automatically adjusted.

Also, in the room 115 there is a human 501 and a mechanical device 5.
There is a heat source such as 02, and there is also a space 1 in the attic.
02 has a heat source such as a lighting fixture 503. The temperature in the room 115 must be controlled in consideration of the heat load caused by these heat generation. However, it is difficult to set the opening degree of the indoor air outlet in consideration of the indoor temperature by trial and error using the actual machine as described above. In particular, since the heat load changes from moment to moment, it is actually extremely difficult to set the opening degree of the indoor air outlet by trial and error in consideration of the fluctuating heat load.

<Objective of the Invention> Therefore, an object of the first invention is to enable the opening degree of an indoor air outlet to be accurately set for a desired air volume without relying on trial and error.

The purpose of this second invention is not based on trial and error,
To enable accurate setting of the opening degree of an indoor air outlet according to heat load.

<Structure of the invention> In order to achieve the above object, this first invention has the following features:
A ductless system that supplies conditioned air from a blower to the space behind the attic through an outlet in the ceiling, uses the space in the attic as an air supply chamber, and supplies conditioned air to the conditioned room from multiple indoor outlets attached to the ceiling. In the air conditioning system, the in-ceiling outlet is configured such that the conditioned air blown out from the in-ceiling outlet flows uniformly in substantially all directions along the ceiling plane,
A model of the ventilation network is set up with the above-mentioned blower and the above-mentioned indoor air outlet as the connection points, and a ventilation network is assumed to connect the connection points with each other. Target air volume (V ₂ ′,
V ₃ ′, V ₄ ′, V ₅ ′), and the specific resistance of the wind duct (R ₁ , R ₆ , R ₇ ,
R ₈ , R ₉ ), and then, in the model of the ventilation circuit network, the amount of pressure drop Fi in each mesh forming the closed circuit in the ventilation circuit network is calculated by calculating the amount of air flowing through the air passage Vi and the specific resistance Ri. Express it as a function and use Kirchhoff's law, which sets each pressure drop amount Fi to zero, to adjust the indoor air outlet so as to obtain the target air volume (V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′). It is characterized in that the opening degree of the indoor air outlet is set by calculating the specific resistance (R ₂ , R ₃ , R ₄ , R ₅ ) of the air duct corresponding to the opening degree.

In addition, the second invention supplies conditioned air from a blower to a space in the attic through an outlet in the ceiling, and uses the space in the attic as an air supply chamber, and air-conditioned air is supplied from a plurality of indoor outlets attached to the ceiling. In a ductless air conditioning system that supplies conditioned air to a room, the in-ceiling outlet is configured such that the conditioned air blown out from the in-ceiling outlet flows uniformly in substantially all directions along the ceiling plane; A model of the ventilation circuit network is set up, with the blower and the indoor air outlet as the connection points, and a wind duct that connects the connection points. Next, the target air duct, which is the desired air volume from the indoor air outlet, is set. In addition to setting the air volume (V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′), the specific resistance of the air volume (R ₁ , R ₆ , R ₇ , R ₈ , R ₉ ) determined by the structure of the building and then
In the model of the above ventilation circuit network, the amount of pressure drop (Fi) in each mesh forming a closed circuit in the above ventilation circuit network is expressed as a function of the air volume (Vi) flowing through the above air duct and the specific resistance (Ri), and each of the above pressures Using Kirchhoff's law, where the amount of descent (Fi) is zero, the air outlet is adjusted to the opening degree of the indoor air outlet so as to obtain the above target air volume (V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′). Calculate the specific resistance of the wind duct (R ₂ , R ₃ , R ₄ , R ₅ ), set the opening degree of the indoor air outlet, and then calculate the air volume supplied to each area (V ₁ , V ₆ , V ₇ , V ₈ , _{V 9} ), the temperature of each area in the ceiling (T ₁ , T ₂ , T ₃ ,
T ₄ ) and the air temperature (T ₁ , T ₂ , T ₃ , T ₄ ) and air volume (V ₁ , V ₂ , V ₃ , V ₄ ) from the indoor air outlets in each area of the ceiling. Calculate the indoor heat supply (C ₁ , C ₂ , C ₃ , C ₄ ) based on
The required amount of indoor heat (A ₁ ′, A ₂ ′, A ₃ ′, A ₄ ′) necessary to reach the above indoor set temperature (Tr) and the amount of indoor heat supplied (C ₁ , C ₂ , C ₃ , C ₄ ), the indoor heat supply (C ₁ , C ₂ , C ₃ , C ₄ ) and the indoor heat requirement (A ₁ ′, A ₂ ′, A ₃ ′, A ₄ ′) are approximately equal. like,
Modify the target air volume (V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′) above, and use Kirchhoff's law again for the above ventilation network to find the specific resistance corresponding to the opening degree of the indoor air outlet. (R ₂ , R ₃ , R ₄ , R ₅ ) is calculated to set the opening degree of the indoor air outlet.

<Examples> The present invention will be described in detail below with reference to illustrated examples.

In Figure 1, 11 is an air-conditioned room, 12 is a ceiling plane, 13 is an upper slab, 15 is a space under the attic, 1
6 is a beam, 501 is a person, 502 is a mechanical device such as an office machine, and 503 is a lighting fixture.

Further, 6 is a blower for supplying conditioned air, 21 is an air supply duct, and 22 is an in-ceiling outlet provided at the tip of the air supply duct 21. This ceiling air outlet 2
2 blows the conditioned air in an upward direction perpendicular to the ceiling plane 12, that is, toward the upper slab 13,
The rebounded air is made to flow uniformly in substantially all directions along the ceiling plane 12. The specific structure of this in-ceiling outlet (hereinafter referred to as a fountain-type in-ceiling outlet) 22 is as shown in FIG.
Conditioned air is gradually blown upward evenly from the entire surface of the perforated plate 201 through the plurality of holes 202, 202, .

In addition, 1, 2, 3, and 4 are indoor air outlets provided in the ceiling plane 12 (indoor air outlets 3 and 4 are indoor air outlets 1,
2, it is located further away from the front of the paper. ), 5 is a return port.

Next, the blower 6 and the indoor air outlets 1, 2,
3 and 4 as connection points, a model of the ventilation circuit network as shown in FIGS. 3 and 4 is set up. As shown by the lines in Figures 3 and 4, each connection point 1, 2,
Assume a wind duct connecting 3, 4, 5, and 6. This air passage is assumed to be an air path that passes under a beam, through an indoor air outlet, etc.

In Figure 4, V ₁ to _{V 9} are the air volume (m ³ /s) flowing through each air duct, and R ₁ to R ₉ are the specific resistance kgf・s ² /
m ⁸ ), q ₂ to _{q 5} are each mesh (closed circuit in the ventilation network)
air volume (m ³ /s). The above specific resistance R ₁ is the resistance of the air supply duct 21, and the specific resistance R ₆ , R ₇ , R ₈ , R ₉
is determined by the structure of the attic space, such as the dimensions under the beams 16 and 16 of the attic space 15, and the resistivity R ₂ , R ₃ , R ₄ , and R ₅ are mainly determined by the indoor air outlet 1,
It is determined by the opening degree of 4, 3, and 2. On the other hand, the relationship between the dimension under the beam and the local resistance in the attic space 15 is as shown in Figure 5, and by adding the specific resistance of the walls in the ceiling to the local resistivity under the beam found from this, the ceiling is determined. Specific resistance of the wind duct in the back space
R ₆ , R ₇ , R ₈ , and R ₉ are determined. In addition, from the graph in Fig. 6 showing the opening degrees and pressure loss of the indoor air outlets 1, 2, 3, and 4, the specific resistance with respect to the opening degrees of the indoor air outlets 1, 2, 3, and 4 is determined, and the known By adding the specific resistances of the air passages in the return port 5 and the air-conditioned room 11, the specific resistances R ₂ , R 3 , R _{4 , and R 5 of the air passages downstream of the indoor air outlets 1, 4, 3 ,} and ₂ are calculated. Seek. Therefore,
Specific resistance R ₂ , R ₃ , R ₄ , R ₅ is indoor air outlet 1, 4,
It is uniquely determined for the opening degrees of 3 and 2.

Now, the following equation holds true for the air volumes V ₁ to V ₉ and the air volumes q ₁ to _{q 5} of the mesh.

V ₁ = q ₁ , V ₂ = q ₁ − q ₂ , V ₃ = q ₂ − _{q 3} V ₄ = q ₃ − q ₄ , V ₅ = q ₄ , V ₆ = q ₂ − q ₅ V ₇ = q ₅ , V ₈ = q ₅ − _{q 4} , V ₉ = q ₃ − _{q 5} (1) On the other hand, the pressure loss h when a unit amount of air passes in a unit time is h = R·V ² .

h: Pressure loss (mmAq or kgf/m ² ) V: Air volume (m ³ /s) R: Specific resistance (kgf・s ² /m ⁸ ) Therefore, for each mesh, air flows in the direction of the arrow in Figure 4. flows, and the following equation holds true with the amount of pressure drop F during this process as functions F ₁ to F ₅ .

F ₁ =R ₁・V ₁・｜V ₁ ｜+R ₂・V ₂・｜V ₂ ｜−Pf F ₂ =R ₂・V ₂・｜V ₂ ｜+R ₆・V ₆ ｜V ₆ ｜+R ₃・_{V 3 ・ | V 3 | _ _ _ _ _ _ _ _} V ₃ ｜＋R ₉・V ₉・｜V ₉ ｜＋R ₄・V ₄・｜V ₄
| F ₂ = R ₂・V ₂・ |V ₂ |+R ₆・V ₆ |V ₆ |+R ₃・V ₃・|V ₃ | F ₃ =−R ₃・V ₃・|V ₃ |+R ₉・V ₉・｜V ₉ ｜＋R ₄・V ₄・｜V ₄
｜ F ₄ = −R ₄・V ₄・｜V ₄ ｜−R ₈・V ₈・｜V ₈ ｜＋R ₅・V ₅・｜V ₅
| F ₂ = R ₂・V ₂・ |V ₂ |+R ₆・V ₆ |V ₆ |+R ₃・V ₃・|V ₃ | F ₃ =−R ₃・V ₃・|V ₃ |+R ₉・V ₉・｜V ₉ ｜＋R ₄・V ₄・｜V ₄
｜ F ₄ = −R ₄・V ₄・｜V ₄ ｜−R ₈・V ₈・｜V ₈ ｜＋R ₅・V ₅・｜V ₅
｜ F ₅ = −R ₆・V ₆・｜V ₆ ｜+R ₇・V ₇・｜V ₇ ｜+R ₈・V ₈・｜V ₈
｜−R ₉・V ₉・｜V ₉ ｜…(2) Here, each mesh constitutes a closed circuit, so
F ₁ =F ₂ =...=F ₅ =0. Note that Pf is the discharge pressure of the blower.

From the above equations (1) and (2), if the specific resistances R ₁ to R ₉ are set, the air volumes V ₁ to _{V 9} can be determined. Further, by setting the air volumes V ₁ to _{V 9} , the specific resistances R ₁ to R ₉ can be determined. Based on this, the opening degrees of the indoor air outlets 1, 2, 3, and 4 are set by a computer as shown in FIG. 7, taking into account the heat load.

First, in step S ₁ , the total amount of heat generated H, the total supply air volume V determined by the ceiling temperature T ₀ of conditioned air and the room temperature setting Tr, and the specific resistance of the air duct including the air supply duct 21 and the attic space 15 are determined. Input R ₁ and the known specific resistances R ₆ to _{R 9} of the air passage in the attic space 15.

Next, proceeding to step _S2 , the room 15 is divided into four areas E ₁ , E ₂ , E ₃ ,
E Divide into ₄ areas and calculate the amount of heat generated indoors corresponding to each area.
Thermal data of A ₁ to A ₄ , the illuminance B ₁ to _{B 4} of the ceiling lighting equipment, that is, the calorific value determined thereby, and the ceiling air temperature T ₀ are input.

Next, proceed to step _S3 and open the indoor air outlet 1,
Assuming specific resistances R ₂ to R ₅ of 4, 3, 2, and considering the above thermal data, the target air volumes of indoor air outlets 1, 4, 3, 2 are determined as V ₂ ′, V ₃ ′, V ₄ ′, Initialize V ₅ ′.

Next, proceed to step _S4 , and use the above equation (1) and
According to equation (2), which sets F ₁ = F ₂ = F ₃ = F ₄ = F ₅ = 0,
Calculate the air volume V ₂ to _{V 9} of each wind duct.

Next, the process proceeds to step _S5 , where the previously calculated air volume from the indoor air outlets 1, 4, 3, and 2 is calculated from V ₂ to _{V 5 .}
is within the allowable range, that is, |Vi−Vi′|/Vi′≦0.01, with respect to the target air volume V ₂ ′, V ₅ ′, and if it is within the allowable range, Assuming that the specific resistances R ₂ to R ₅ assumed earlier are appropriate, proceed as follows.
Proceed to S ₇ . On the other hand, if the calculated blowout air volumes V ₂ to V ₅ are not within the allowable range with respect to the target air volumes V ₂ ′ to _{V 5} ′, the process proceeds to step S ₆ .

In step _S6 , the previously assumed specific resistances _R2 to _R5 are determined to be inappropriate, and the specific resistances _R2 to _R5 are newly set using the following formula, and the process returns to step _S4 .

Ri←Ri×√′ In this way, the air volume V ₂ ~ V ₅ calculated by applying Kirchhoff's law without convection is compared with the target air volume V ₂ ′ ~ V ₅ ′ to reach the desired air volume. until it becomes
Opening degree of indoor air outlet (i.e. specific resistance of air outlet)
By changing and setting , it is possible to easily and accurately determine the optimal opening degree of the indoor air outlet without relying on trial and error using the actual machine.

Next, proceeding to step _S7 , as shown in FIG. 16, the temperature _T1 in each area _E1 ' to _E4 ' in the ceiling is
~Calculate _T4 . This temperature T ₁ to _{T 4} is the ceiling surface 12
and the heat flowing through the slab 13 and the lighting fixture 50
3,503,... and the amount and temperature of conditioned air supplied to each area.

Next, proceeding to step _S8 , the temperatures T ₁ to T 4 of each area E ₁ ′ to _{E 4} ′ in the ceiling, that is, the temperature of the indoor blowing air T ₁ to _{T 4 and} the blowing air volume V ₁ to V ₄ are determined. Based on the indoor heat supply from each indoor outlet 1 to 4 C ₁
~Calculate _C4 .

Next, proceed to step S ₉ to check each area in the room.
The required amount of heat A _{1 ′} to _{A 4} ′ in E 1 to E ₄ is calculated from the temperature of each area E ₁ ′ to _{E 4} ′ in the ceiling, the amount of indoor heat generated A ₁ to _{A 4} , and the indoor set temperature Tr. For example, as follows.

A ₁ ′=A ₁ −(Tr−T ₀ )K Here, K is the heat transmission coefficient of the ceiling surface.

Next, proceed to step S ₁₀ to supply the amount of heat C ₁ ~
Determine whether C ₄ is within the allowable range for the required heat amount A ₁ ′ to A ₄ ′, that is, |Ai′−Ci|<Ci≦0.01, and if it is within the allowable range, step
Proceed to _S12 and set the target air volume V ₂ ′ to V ₅ ′ assumed earlier, the specific resistance R ₂ to _{R 5} of the indoor air outlet, and the opening degree of the air outlet 1 to 4 assuming that they are appropriate. Output. On the other hand, if it is not within the allowable range, proceed to step _S11 and set the target air volume V ₂ ′ to
V ₆ ′ is corrected, the process returns to step S ₄ , and the series of steps described above is repeated until the amount of heat supplied to the room C ₁ to C ₄ or the amount of heat required for the room becomes approximately equal to the amount of heat A ₁ ′ to A ₄ ′.

The ventilation circuit network shown in Figures 1, 3, and 4 is as follows:
Although the conditioned air coming out of the blower 6 is directly returned to the blower 6 from the attic space 15 via the conditioned room 11, the present invention is not limited to this. When going outdoors, the blower 6 sucks in that amount of outdoor air and sends it to the attic space 15. Figures 3 and 4 show the ventilation circuit network in this case. Become.

In addition, in the above example, the resistivity R ₂ to _{R 9} was determined by numerical analysis, but the resistivity R ₂ to _{R 5} was determined by algebraic calculation with the target air volume V ₂ ′ to _{V 5} ′ being known. Good too.

Figures 8 and 9 show a first experimental example set up using the method of the present invention. In this experimental example, a fountain-type ceiling air outlet 6 shown in FIG. 2 is used as the ceiling air outlet, and there is a beam in the attic space.

As can be seen from the arrows indicating the wind direction in Figure 8, no convection is occurring in the attic space. Furthermore, as can be seen from FIG. 9, the calculated values of air volume enclosed in parentheses and the measured values of air volume not enclosed in parentheses are in good agreement. This is considered to be because no convection is occurring in the attic space 15.

Figures 10 and 11 show the second
An experimental example is shown. In this experimental example, a fan-shaped or diffused-type in-ceiling outlet 35 shown in Fig. 12 that blows out conditioned air in all directions parallel to the ceiling plane is used as the in-ceiling outlet, and there is a beam in the ceiling space. , and there are obstacles 36 that are not air-conditioned, such as elevators.

FIG. 10 shows the static pressure distribution in the attic space, and it can be seen that the static pressure is uniformly or entirely reduced from the in-ceiling air outlet 35, and no convection is occurring. Furthermore, from FIG. 11, it can be seen that the measured values and calculated values agree well.

<Effect of the invention> As is clear from the above, this first invention has the following effects:
Assuming that there is no convection in the space behind the ceiling and assuming a ventilation network, we set the opening of the indoor air outlet to obtain the target air volume using Kirchhoff's law, so we conducted a trial run on the actual machine. To easily and accurately set the optimum opening degree of an indoor air outlet without making mistakes. In addition, since the air volume from the indoor air outlet can be predicted, in a ductless air conditioning system, the blower discharge volume and the opening degree of the indoor air outlet can be adjusted according to changes in the indoor heat load or seasonal changes. Automatic adjustment can be made accordingly.

Further, in addition to the configuration of the first invention, the second invention makes the amount of heat supplied indoors equal to the amount of heat required indoors, so in addition to the effects of the first invention,
The opening degree of the indoor air outlet can be easily and accurately set according to the heat load.

[Brief explanation of drawings]

Fig. 1 is a sectional view of one embodiment of the present invention;
Figure 12 is a perspective view of the air outlet in the ceiling, 3rd and 4th figures.
The figure shows the ventilation circuit network, Figures 5 and 6 show the resistance under the beam and characteristics of the indoor air outlet, Figure 7 shows the flowchart, and Figures 8, 9, 10, and 11 show the experimental data. 13 and 14 are vertical and horizontal sectional views of the conventional example, FIG. 15 is a plan view illustrating the ceiling and the interior area, and FIG. 16 is an enlarged view of the attic space. 1, 2, 3, 4...Indoor air outlet, 6...Blower, 1
1...Air conditioned room, 15...Space behind the ceiling, 22, 35
...Air outlet in the ceiling.

Claims (1)

[Scope of Claims] 1. Conditioned air from a blower is supplied to the space in the attic from an outlet in the ceiling, the space in the attic is used as an air supply chamber, and the conditioned air is supplied to the air-conditioned room from a plurality of indoor outlets attached to the ceiling. In a ductless air conditioning system that supplies conditioned air to A model of the ventilation circuit network is set up assuming a wind duct that connects the connection points with the above indoor air outlet as the connection point, and then a target air volume of the wind duct that is the desired air volume from the indoor air outlet is set. (V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′), and the specific resistance of the wind duct (R ₁ , R ₆ , R ₇ , R ₈ , R ₉ ) determined by the structure of the building. Next, in the model of the ventilation circuit network, the amount of pressure drop (Fi) in each mesh forming the closed circuit in the ventilation circuit network is expressed as the amount of air flowing through the air passage (Vi) and the specific resistance (Ri). Using Kirchhoff's law, which expresses the pressure drop as a function and sets each pressure drop (Fi) to zero, the indoor airflow is calculated to obtain the target air volume (V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′). A ductless air conditioner characterized in that the opening degree of the indoor air outlet is set by calculating the specific resistance (R ₂ , R ₃ , R ₄ , R ₅ ) of the air duct corresponding to the opening degree of the outlet. How to set the opening of the indoor air outlet in the system. 2 The in-ceiling outlet is oriented in a direction perpendicular to the ceiling plane, and after the air blown out from the in-ceiling outlet collides with the slab or ceiling surface, it flows uniformly in substantially all directions along the ceiling plane. A method for setting the opening degree of an indoor air outlet in a ductless air conditioning system according to claim 1. 3 Supply conditioned air from the blower to the space behind the attic through the air outlet in the ceiling, use the space in the attic as an air supply chamber, and supply conditioned air to the conditioned room from multiple indoor air outlets attached to the ceiling. In the ductless air conditioning system, the ceiling air outlet is configured such that the conditioned air blown out from the ceiling air outlet flows uniformly in substantially all directions along the ceiling plane, and the air blower and the indoor air outlet are connected to each other. We set up a model of the ventilation network that assumes air ducts that connect the connection points as connection points. Next, we calculate the target air volume of the wind duct (V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′), and the specific resistance of the wind duct (R ₁ , R ₆ , R ₇ , R ₈ , R ₉ ) determined by the structure of the building, and then , In the model of the ventilation circuit network, the amount of pressure drop (Fi) in each mesh forming a closed circuit in the ventilation circuit network is expressed as a function of the air volume (Vi) flowing through the air duct and the specific resistance (Ri), and each of the above Using Kirchhoff's law where the pressure drop (Fi) is zero, the opening of the indoor air outlet is adjusted to obtain the above target air volume (V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′). Calculate the specific resistance (R ₂ , R ₃ , R ₄ , R ₅ ) of the air duct to set the opening degree of the indoor air outlet, and then calculate the air volume supplied to each area (V ₁ , V ₆ ,
V ₇ , V ₈ , V ₉ ), the temperature of each area in the ceiling ₍ T ₁ , T ₂ , T ₃ , T ₄ ) and the air temperature (T ₁ , T ₂ , T ₃ , T ₄ ) and air volume (V ₁ , V ₂ , V ₃ , V ₄ ) from the indoor air outlets in each area of the ceiling. Calculate the indoor heat supply (C _{1 ,} C ₂ , C ₃ , C ₄ ) based on ₂ ′, A ₃ ′, A ₄ ′) and the indoor heat supply (C ₁ , C ₂ , C ₃ , C ₄ ),
_{The above - mentioned target air volume (} V ₂ ′, V ₃ ′, V ₄ ′, V ₅ ′), and again apply Kirchhoff's law to the above ventilation network to find the specific resistance (R ₂ , A method for setting the opening degree of an indoor air outlet in a ductless air conditioning system, characterized in that the opening degree of the indoor air outlet is set by calculating R ₃ , R ₄ , R ₅ ). 4 The in-ceiling outlet is oriented in a direction perpendicular to the ceiling plane, and after the air blown out from the in-ceiling outlet collides with the slab or ceiling surface, it flows uniformly in substantially all directions along the ceiling surface. A method for setting the opening degree of an indoor air outlet in a ductless air conditioning system according to claim 3.